So if we take 1/4 to be the 100%, what is 2/3 in percentage off of it then?

yes, is a large value, because 2/3 is indeed larger than 1/4, more than twice as large.
You need to go to school sorry I don’t know I just joined sorry
Answer:
25 percent.
Step-by-step explanation:
15 is 1/4 of 60 and if she gets 1/4 off then that's equal to 25 percent
Part A:
From the graph, it seems that the lines intersect at (3,-1)... This seems to be the solution...
Part B:
g(x) is a negative line, and the slope is 2 (from rise/run). Y int. = 5. So, the equation is -2x+5. Plug in some numbers for this; say 1 and 2. The coordinates would be (1,3) and (2,1).
Part C:
The 2 graphs seem to intersect at (0,5), so this is the solution...
ALL of this is based on only looking at the graph, which is no better than drawing lines on the sand.. For example, the y intercept for g(x) could be 4.9 or 5.1, and I don't know the equation for f(x)... Based on the info I have, gave my best answers..
Hope this helps..