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ruslelena [56]
3 years ago
10

Condition (0°≤A≤360°)sin5A+sin3A=cos2A-cos6A​

Mathematics
1 answer:
Solnce55 [7]3 years ago
4 0

Answer:

sin5A+sin3A=cos2A-cos6A

2SIN((5A+3A)/2)COS ((5A-3A)/2)=2SIN((2A+6A)/2)SIN((2A-6A)/2)

\frac{2 \sin(4a )cosa}{ - 2 \sin(4a)  \sin(2a) }  = 1

-  \frac{ \cos(a) }{2 \sin(a) \cos(a )  }  = 1

-1/2sinA=1

-1/2=sinA

sinA=sin(180+30),sin(330)

:.A=210,330

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6 0
3 years ago
Find the slope-intercept form of an equation for the line that passes through (–1, 2) and is parallel to y = 2x – 3.
sukhopar [10]

Answer:

Option d is the correct answer

Step-by-step explanation:

The slope-intercept form of an equation for a line passing through given points can be represented as

y = mx + c

Where

Slope, m = (change in value of y on the vertical axis) / (change in value of x on the horizontal axis)

c = y-intercept

We want to find the slope-intercept form of an equation for the line that passes through (–1, 2) and is parallel to y = 2x – 3

For two lines to be parallel to each other, the slopes must be equal.

For y = 2x – 3

Slope,m = 2 (comparing with the slope intercept form stated above).

This means that the slope of the line

that passes through (–1, 2) is also 2

To find the y-intercept, c of this equation,

2 = 2 × - 1 + c

2 = -2 + c

c = 2+2 = 4

The equation is

y = 2x + 4

8 0
3 years ago
Label each tick mark with its location on the number line:
Aleksandr-060686 [28]
From my understanding the question is basically asking u to label each Dash/tick mark on the line. They have already given u 0 as the first one, 24 as the fifth one and 60 as the eleventh one. I’m assuming u can use any method.
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First line: 0
Second line: 6
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4 0
3 years ago
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<

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<

8 0
3 years ago
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