Answer:
It should I only looked at the first few columns and the matched up
Step-by-step explanation:
Pemdas
parenthasees exponents mult/division additon/subtraction
parethenasees
x-3 and x+5 we can't do anything with so next
5(x-3)=5x-15
2(x+5)=2x+10
5x-15+2=5x-13
(2x+10-9)=2x+1
(5x-13)-3(2x+1)
-3(2x+1)=-6x-3
5x-13-6x-3=-x-16
4(-x-16)=-4x-64
the answer is -4x-64
We know that the area of a circle in terms of π will be πr². However the area with respect to the diameter will be a different story. The first step here is to find a function relating the area and diameter of any circle --- ( 1 )
For any circle the diameter is 2 times the radius,
d = 2r
Therefore r = d / 2, which gives us the following formula through substitution.
A = π(d / 2)² = πd² / 4
<u>Hence the area of a circle as the function of it's diameter is A = πd² / 4. You can also say f(d) = πd² / 4.</u>
Now we can substitute " d " as 4, solving for the area ( A ) or f(4) --- ( 2 )
f(4) = π(4)² / 4 = 16π / 4 = 4π - <u>This makes the area of circle present with a diameter of 4 inches, 4π.</u>
