Angle <QAB is =15° because the opposite angles of an isosceles triangle are equal.
The length of the straight line AB = 80cm
<h3>Calculation of angle of a triangle</h3>
The angle at a point = 360°
Angle AQB= 360 - 210° = 150
But the angle that makes up a triangle= 180°
180-150= 30°
But <QAB = <QBA because triangle AQB is an isosceles triangle.
30/2 = 15°
To calculate the length of the straight line the following is carried out using the sine laws.
a/ sina, = b sinb
a= 8cm, sin a { sin 15)
b= ? , sin B = 150
make b the subject formula;
8/sin15= b/sin 150
b= 8 × sin 150/sin 15
b= 80cm
Learn more about isosceles triangle here:
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Answer:
b
Step-by-step explanation:
#2 is answer 4, #3 is answer 3, #4 is answer 4. The answer to #5 is 6xy if it is a possibility.
Option B:
sin x = 1 is the equation represented by the intersection of the graph.
Solution:
The graph lies between -1 and 1 in y-axis.
x-axis of the graph is all real numbers.
The graph oscillates between -1 and 1 and a shape that repeats itself every 2π units.
That is the domain of the graph is all real numbers.
The range of the graph is [-1, 1].
It clearly shows that, it is the graph of sinx = 1.
Hence sin x = 1 is the equation represented by the intersection of the graph.
Option B is the correct answer.
Answer:
106°
Step-by-step explanation:
Supplementary angles total 180°, so the one supplementary to 74° is ...
180° -74° = 106°
