3 years ago

¿cuales son las funciones de sunass, osinergmin y osiptel?

Mathematics

1 answer:

evablogger [386]3 years ago

5 0

Answer:

la verdD no c

Step-by-step explanation:

pero tu pon lo q creas nadie es perfecto

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Determine which values of p the following integrals converge. Give your answer in each case by selecting the appropriate inequal

sashaice [31]

Answer:

Step-by-step explanation:

$\int\limits^2_1 {\frac{1}{x(lnx)^p} } \, dx$

this can be done by substitute lnx = u

dx/x = du

When x =1, u =0 and when x =2, u = ln 2

So integral = $\int\limits^{ln2} _0 {du/u^p} \\\=\frac{u^{-p+1} }{-p+1}$

We find that this integral value is not definid for p =1

Hence for values of p other than 1, this converges.

When we substitute limits

$\frac{1}{1-p} ((ln2)^{1-p} -1)$

and converges for p ≠1

b) $\int\limits^1_0 {lnx}/x^p \, dx \\\int \frac{\ln \left(x\right)}{x^p}dx=\frac{1}{-p+1}x^{-p+1}\ln \left(x\right)-\frac{x^{-p+1}}{\left(-p+1\right)^2}+C$

So not converging for p =1

But ln x is defined only for x >0

So integral 0 to 1 makes this integral not valid and hence not convergent.

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George ran 1000 yards in gym class. how many kilometers did he run?

Sliva [168]

He ran 7 kilometers.

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4 years ago

5+6x-3y+x+8y<br><br> please im dumb lol

-Dominant- [34]

Answer:

7x+5y+5

Step-by-step explanation:

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Step-by-step explanation:

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