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lbvjy [14]
3 years ago
5

¿cuales son las funciones de sunass, osinergmin y osiptel?

Mathematics
1 answer:
evablogger [386]3 years ago
5 0

Answer:

la verdD no c

Step-by-step explanation:

pero tu pon lo q creas nadie es perfecto

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Determine which values of p the following integrals converge. Give your answer in each case by selecting the appropriate inequal
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Answer:

Step-by-step explanation:

a)

\int\limits^2_1 {\frac{1}{x(lnx)^p} } \, dx

this can be done by substitute lnx = u

dx/x = du

When x =1, u =0 and when x =2, u = ln 2

So integral = \int\limits^{ln2} _0 {du/u^p} \\\=\frac{u^{-p+1} }{-p+1}

We find that this integral value is not definid for p =1

Hence for values of p other than 1, this converges.

When we substitute limits

\frac{1}{1-p} ((ln2)^{1-p} -1)

and converges for p ≠1

b) \int\limits^1_0 {lnx}/x^p \, dx \\\int \frac{\ln \left(x\right)}{x^p}dx=\frac{1}{-p+1}x^{-p+1}\ln \left(x\right)-\frac{x^{-p+1}}{\left(-p+1\right)^2}+C

So not converging for p =1

But ln x is defined only for x >0

So integral 0 to 1 makes this integral not valid and hence not convergent.

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4 years ago
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He ran 7 kilometers.

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