A) The inverse of the statement is the opposite. The statement stated that if two lines do not intersect, they are parallel. So, the opposite would be if two lines intercept, they are parallel. This inverse statement is false because, that is not true. Parallel lines mean they never intercept, not if they intercept its parallel.
b) Converse means to engage or explain, I think…so, the converse of the statement would be that yes, it is true that when two lines do not intercept then they are parallel. Because parallel lines never cross or meet, meaning they will NEVER ever have a crossing point.
c) the contrapositive of the statement would be: if two lines do not cross then they are parallel. If they do intercept, then they are not parallel. As simple as that. I think contrapositive means that…I looked what contrapositive means…so I think I’m right.
I hope this helps!! Or some at least. :)
Good luck!
Answer: The equation of the circle is

Step-by-step explanation: We are given to write the equation of the circle with radius √13 units and center at the point (-9.3, 4.1).
We know that
the standard equation of a circle with radius r units and center at the point (h, k) is given by

In the given circle,
radius, r = √13 units and center, (h, k) = (-9.3, 4.1).
Therefore, the equation of the circle will be

Thus, the equation of the circle is

You first switch f(x) with x in this equation
<span>x=<span>1<span>9f(x)−2</span></span></span>
Then you solve for f(x).
<span>9f(x)−2=<span>1x</span></span>
<span>9f(x)=<span>1x</span>+2</span>
<span>f(x)=<span>1<span>/9x</span></span>+<span>2/9</span></span>
Then you simply repalace f(x) with f^-1(x)
It will look like this
<span><span>f−</span>1(x)=<span>1<span>/9x</span></span>+<span>2/<span>9
Hope i could help
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Answer:
2 5/16
Step-by-step explanation:
step by step instructions are in pic below
Period is from 0 to 2pi
take the deritivive then take it again
we get f''(x)=-4cos²(x)-2cos(x)+2
it is negative between 0 and pi/3 and also between 5pi/3 and 2pi
concave down in the interval
![[0, \frac{ \pi }{3}]](https://tex.z-dn.net/?f=%5B0%2C%20%5Cfrac%7B%20%5Cpi%20%7D%7B3%7D%5D)
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