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3 years ago

Please answer both ASAP (middle school) (probability)

Mathematics

1 answer:

lana66690 [7]3 years ago

7 0

Answer:

the first one is 18/32 and the second one is 125 games or 120

Step-by-step explanation:

for the first add all the numbers to get your denominator then add the probability of green aND YELLOW.

for the second you just divide 200 by eight to get 25 then times 25 by 5 to get your anwser

hope this helped :)

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Xin answered 182 questions correctly on her multiple choice math final that had a

miv72 [106K]

Answer:

91%

Step-by-step explanation:

182/200 = .91

.91 = 91%

Hope that helps!

7 0

3 years ago

Austin qualified for a $30,000 loan with 7.49% interest in order to buy a new ski boat. The term of his loan is 10 years and his

sertanlavr [38]

Answer:

$12,714

Step-by-step explanation:

Loan Amount=$30,000

Monthly Payment =$355.95.

Number of Payment Period = 10 Years X 12 Months =120 Months

Total Payment to be made by Austin =120 X 355.95=$42,714

Therefore:

The interest Austin will pay=Total Payment-Loan Amount

=$42,714-30,000

=$12,714

7 0

3 years ago

The Bulldog soccer team wants to increase the size of its practice field by a scale factor of 1.5. The field is a rectangle that

forsale [732]

95ft hope this helps

8 0

3 years ago

The National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time requir

Paha777 [63]

Answer:

95% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

Step-by-step explanation:

We are given that the National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time required to earn their bachelor’s degrees. The mean was 5.15 years and the standard deviation was 1.68 years respectively.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean time = 5.15 years

$\sigma$ = sample standard deviation = 1.68 years

n = sample of college graduates = 4400

$\mu$ = population mean time

Here for constructing 95% confidence interval we have used One-sample z test statistics although we are given sample standard deviation because the sample size is very large so at large sample values t distribution also follows normal.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $5.15-1.96 \times {\frac{1.68}{\sqrt{4400} } }$ , $5.15+1.96 \times {\frac{1.68}{\sqrt{4400} } }$ ]

= [5.10 , 5.20]

Therefore, 95% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

8 0

3 years ago

Solve for x. 8x^2−3=2

sergeinik [125]

8x^2=2+3

8x^2=5

x^2=5/8

x= sqrt(5/8)

5 0

3 years ago