Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
Answer is B. second one
A = 1/8, B = 5/16, C = 7/12, D = 5/6
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The two numbers are 5 and 12.
1468 is the answer.
You have to find the volume of the large shape and subtract the volume of the small shape. Write the equation as such:
(10*10*15) -(2*4*4)
1500 -32
1468
