The completely factored expression of 2x^2 + 4x + 3xy + 6y is (2x + 3y)(x + 2)
<h3>How to factor the polynomial?</h3>
The expression is given as:
2x^2 + 4x + 3xy + 6y
Group the expression into two
[2x^2 + 4x] + [3xy + 6y]
Factor out each group
2x(x + 2) + 3y(x + 2)
Factor out x + 2
(2x + 3y)(x + 2)
Hence, the completely factored expression of 2x^2 + 4x + 3xy + 6y is (2x + 3y)(x + 2)
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Answer:
4x
Step-by-step explanation:
it will always be the Number beside the variables
Step-by-step explanation:
First you change them to improper fractions. 10/3 and 5/3
Next you subtract 10 and 5 which is obviously 5
Then you have 5/3 turning that to a mixed number makes it 1 2/3
Hope this helps!
(y-y1)=m(x-x1)
y-(-2)=4(x-3)
y+2=4x-12
y=4x-14
