The answer is it equals 0
Answer:
5
Therefore, she must get 5 points from the last quiz to have a mean score of 4
Step-by-step explanation:
Mean is the average of a set of data, it is the sum of the data divided by the number of data.
To have a mean of 4 from 4 quizzes;
Let x represent the total;
mean = x/4
4 = x/4
x = 4 × 4 = 16
To have a mean of 4 he must have a total score of 16.
Let y represent her score in the last quiz;
16 = 4+3+4+y
16 = 11+y
y = 16-11 = 5
Therefore, she must get 5 points from the last quiz to have a mean score of 4
Answer:40.00
Step-by-step explanation:just add
Answer:
- 13 - 23 = - 13 + (-23)
= -36
- 13 - (- 23) = - 13 + 23
= 10
Step-by-step explanation:
In any order of operation (i.e. addition, subtraction, multiplication, devision) the following rules apply for two values for instance <em>a </em>and <em>b </em>where <em>a > b </em>:
→ <em>If +a and +b then the final sign will be + (positive)</em>
→ <em>If +a and -b then the final sign will be + (positive) since a>b</em>
→ <em>If -a and +b then the final sign will be - (negative) since a>b</em>
→ <em>If -a and -b then the final sign will be - (negative)</em>
In the given question we have two cases.
Case 1:
- 13 - 23 = - 13 + (-23) <em>→ since it is given that we add a negative value of -23, therefore it keeps its sign (so this would be a negative addition i.e. adding two negative values)</em>
Thus we have:
- 13 - 23 = - 13 + (-23)
= -36
Case 2:
- 13 - (- 23) = - 13 + 23 <em>→ since we stated earlier that - and - gives positive sign (i.e. we subtract two negative values)</em>
Thus we have:
- 13 - (- 23) = - 13 + 23
= 10
<em>So we can see that: </em>
<em>Adding two Negative values gives a Negative value (Case 1)</em>
Subtracting two Negative values gives a Positive value (Case 2)
Answer:
T = - 7.5 Cos π/12( t - 4 ) + 10.5
Step-by-step explanation:
Given that the
Maximum temp. = 18 degree Celsius
Minimum temp. = 3 degree Celsius
The half way between 10 am and 10 pm is 4 am
The sine and cosine functions can be used to model fluctuations in temperature data through out the year. An equation that can be used to model these data is of the form:
T = A cos B(t - C) + D, where A,B,C,D, are constants, T is the temperature in °C and t is the hour (1–24)
A = amplitude = (Tmax - Tmin)/2
A = (3 - 18)/2 = - 15/2 = -7.5 ( note : after midnight)
B = 2π/24 = π/12
C = units translated to the right
C = 4
D = ymin + amplitude = units translated up
D = 7.5 + 3 = 10.5
The formula of the trigonometric function that models the temperature T in Johannesburg t hours after midnight we be
T = - 7.5 Cos π/12( t - 4 ) + 10.5
