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sp2606 [1]
2 years ago
14

Find the volume of the following cylinder in CENTIMETRES CUBED.

Mathematics
1 answer:
mash [69]2 years ago
3 0
The answer is 3.93 cm
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Show the working out too please in numbers, thank you.
vazorg [7]

Hii :))

\tt \: - 5 =  \frac{x}{6}  \\   \tt \:  - 5 \times 6 = x \\  \boxed{  \tt \:  - 30 = x}

__________________

  • The correct value of x is <u>-</u><u> </u><u>3</u><u>0</u><u>.</u>

\overbrace{ \underbrace{ \sf \: \infty  \:  Carry \: on \: Learning \:  \infty }}

ᴛʜᴇᴇxᴛʀᴀᴛᴇʀᴇꜱᴛʀɪᴀʟ

3 0
2 years ago
Read 2 more answers
Divide.<br><br> (<img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20" id="TexFormula1" title=" x^{2} " alt=" x^{2} " align="absm
Maksim231197 [3]
    (x+6)^2 
----------------
x^4+11x+30
6 0
3 years ago
I need help with this problem
-BARSIC- [3]
Regular is
$97.99 after sale price is 83.30
97.99- 83.30= 14.69 is the discount
You can do it same way with B C and D
6 0
3 years ago
What are the x intercept and y intercept of the graph of 5x+8y=20
Arada [10]

Answer:

x intercept: (4,0)

y intercept: (0,2 1/2)

Step-by-step explanation:

4 0
2 years ago
Two balls are drawn in succession out of a box containing
victus00 [196]
There are a total of 8 balls 

The probability of drawing a white ball is 4/8 on the first draw.
If you replace the ball then the probability will still be 4/8 for a white ball, since these events are independent of each other you multiply 4/8 x 4/8 = 16/64 or 1/4 then the probability of drawing at least 1 red ball with replacement is 1 - 1/4 = 3/4

Now without replacement:
the probability of drawing a white ball is 4/8 since you don't replace the ball then the probability of drawing a white ball the second time is 3/7 again multiply these two probabilities: 4/8 x 3/7 = 12/56 the the probability of drawing at least 1 red ball is 1- 12/56 = 44/56 or 11/14
4 0
2 years ago
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