First some rewriting:
We see that the numerators of both fractions 
and a term in the denominators 
will cancel:
Then
First, put ur equation in y = mx + b form
y - 6x - 9 = 0
y = 6x + 9
now, to put it in function notation, sub in f(x) for y
f(x) = 6x + 9 <== function notation
Step-by-step explanation:
First she need to measure the complete wall distance and then divide it by 2
(I just tried the answer, Sorry if it is wrong)
We need not go so depth in this question and find it logically.
Answer:
7/18
Step-by-step explanation:
Total Number of Boys in both grades:
4+3=7
Total Number of Students:
8+10=18
Number of boys/ number of students:
7/18
Solution:
we have been asked to find the solution of the equation
It can be solved using factoring as below:
![x^6 + 6x^3 + 5 = 0\\\\substitute, x^3=y\\\\y^2+6y+5=0\\\\y^2+5y+y+5=0\\\\y(y+5)+1(y+5)=0\\\\(y+5)(y+1)=0\\\\y=-1,-5\\\\\text{substitute back }y=x^3\\\\x^3=-1,-5\\\\x=-1,\sqrt[3]{-5} \\\\\text{These are the only real solutions}\\](https://tex.z-dn.net/?f=x%5E6%20%2B%206x%5E3%20%2B%205%20%3D%200%5C%5C%5C%5Csubstitute%2C%20x%5E3%3Dy%5C%5C%5C%5Cy%5E2%2B6y%2B5%3D0%5C%5C%5C%5Cy%5E2%2B5y%2By%2B5%3D0%5C%5C%5C%5Cy%28y%2B5%29%2B1%28y%2B5%29%3D0%5C%5C%5C%5C%28y%2B5%29%28y%2B1%29%3D0%5C%5C%5C%5Cy%3D-1%2C-5%5C%5C%5C%5C%5Ctext%7Bsubstitute%20back%20%7Dy%3Dx%5E3%5C%5C%5C%5Cx%5E3%3D-1%2C-5%5C%5C%5C%5Cx%3D-1%2C%5Csqrt%5B3%5D%7B-5%7D%20%5C%5C%5C%5C%5Ctext%7BThese%20are%20the%20only%20real%20solutions%7D%5C%5C)
