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nadya68 [22]
2 years ago
5

How many real solutions exist for this system of equations?

Mathematics
1 answer:
Rom4ik [11]2 years ago
7 0

Answer:

One

Step-by-step explanation:

Set each equations equal to each other

{x}^{2}  + 4 = 4x

{x}^{2}  - 4x + 4

Find the discrimant.

{ - 4 {}^{2} - 4(1)(4) } = 0

This means there is one real solution. Since the discramnt equal 0.

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i think of a number. if i divide the sum of 6 and the number by 3, the result is 4 more than one quarter of the number. find the
slega [8]

Answer:

-12

Step-by-step explanation:

Let the number be A

Given if you divide the sum of six and the number A by 3 , the result is 4 more than 1/4 of A

That’s

6+A/3 = 4+1/4 of A

6+A/3 = 4+1/4 x A

6+A/3 = 4+A/4

Cross multiply

4(6 + A) = 3(4 + A)

Distribute

4 x 6 + 4 x A = 3 x 4 + 3 x A

24 + 4A = 12 + 3A

Subtract 24 from both sides to eliminate 24 on the left side

24 - 24 + 4A = 12 - 24 + 3A

4A = -12 + 3A

Subtract 3A from both sides so the unknown can be on one side

4A - 3A = -12 + 3A - 3A

A = -12

Check

6+(-12)/3 = 4 +(-12)/4

6 -12/3 = 4 -12/4

-6/3 = -8/4

-2 = -2

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3 years ago
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romanna [79]
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Answer:

A.385.33

Step-by-step explanation:

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240÷2=120

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530/2=265

265+120=385

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