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nadya68 [22]
2 years ago
5

How many real solutions exist for this system of equations?

Mathematics
1 answer:
Rom4ik [11]2 years ago
7 0

Answer:

One

Step-by-step explanation:

Set each equations equal to each other

{x}^{2}  + 4 = 4x

{x}^{2}  - 4x + 4

Find the discrimant.

{ - 4 {}^{2} - 4(1)(4) } = 0

This means there is one real solution. Since the discramnt equal 0.

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9+2×42+6-2<br><br>Please show the work​
timofeeve [1]

Answer:

The answer is 97

Step-by-step explanation:

According to PEMDAS, we will solve the multiplication first. 2 × 42 is 84. Next, we will add or subtract from left to right. 9 + 84 + 6 – 2 is 97, the answer to our problem.

8 0
1 year ago
Read 2 more answers
Guys do anybody know the answer to this????????????????
sergejj [24]

Answer:

find where they intersect on the graph or find each line's individual equation and set them equivalent to eachother. x=2

8 0
2 years ago
Explain your answer !! <br> Have a nice day <br><br> Will give braisnlt
11111nata11111 [884]

Answer:

The price of hot dog is $2.5 and that of a pretzel is $1.25.

Step-by-step explanation:

Let the cost of hotdogs be x and that of pretzels be x.

So,

4x+3y = 13.75 ...(1)

and

2x+5y = 11.25 ...(2)

Multiply equation (2) by 2.

4x+10y = 22.5 ...(3)

Subtract equation (1) from (3).

4x+10y-(4x+3y) = 22.5-13.75

4x+10y-4x-3y = 8.75

7y = 8.75

y = 1.25

Put the value of y in equation (1).

4x+3(1.25) = 13.75

4x+3.75 = 13.75

4x = 13.75-3.75

4x = 10

x = 2.5

So, the price of hot dog is $2.5 and that of a pretzel is $1.25.

3 0
2 years ago
Four friends went to the movies each ticket cost $8 and each person bought popcorn and a soda for $5 how much did they spend in
Neporo4naja [7]
Answer: m = $52

Explanation:
Tickets (t) = $8
Popcorn & Soda (s)= $5
Friends = 4
Since all friends bought the same thing the equation will be set as
4(t +s) = m OR 4t +4s = m
Using substitution, you plug each variable
t = 8 and s = 5
4((8) + (5)) = m
4(8+5) = m => 4(13) =m => 52=m
OR
4(8) + 4(5) = m => 32 + 20 = m =>
52 =m
7 0
3 years ago
Which of these choices show a pair of equivalent expressions?
NISA [10]

Answer:

A. 6^2/7 and (√6)^7

Step-by-step explanation:

Because we can't get 6 out of root as a whole we need to use the power to show its value when we do so.

The power of (√6)^7 has is seven and degree of the root is 2 so we have to put 2/7 over 6 when we take it out of root.

6 0
2 years ago
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