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Maurinko [17]
2 years ago
7

There are 110 sixth-grade students in a Florida middle school. 40% of the students enjoy playing video games on the weekends. Us

ing the percent as a rate per 100, how many students enjoy playing video games?
Mathematics
1 answer:
andreyandreev [35.5K]2 years ago
7 0
40/100 - (I may be wrong)

Explanation: 40% of 110 is 44 so we make this a fraction 44/110 and then simplify to get 2/5 and after that we know that 2/5 is also 40/100, meaning 40 out of 100 students like video games.
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CAN SOMEONE HELP ME UNDERSTAND THIS PLEASE
ICE Princess25 [194]

YEAH OFC SHAWTY!

  • so for A its -4^11 because if the powers have the same base and they are being multiplied you add the powers
  • For B its the same idea, they have the same base, and are being multiplied so you add the powers- 13^9
  • For C its similar, you have the same base, but since its Dividing, you subtract the powers. So, 9^5
  • for D you pretend like the denominator has a power of 1 and subtract. So its -24^5-24^1 which hopefully puts it into perspective of being -24^4 becuase we subtracted the powers

I cant do 2 right now, but i will in a minute

<u>And for 3 his mistake is that they arent the same bases so he cant add the powers, he should have converted them to the same base first. </u>

7 0
3 years ago
What are the domain restrictions of the function f(x) = the quantity of x squared plus 6x plus 9, all over 3x plus 15.
dangina [55]

Answer:

x = - 5

Step-by-step explanation:

Given

f(x) = \frac{x^2+6x+9}{3x+15}

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.

solve : 3x + 15 = 0 ⇒ 3x = - 15 ⇒ x = - 5 ← excluded value

Domain x ∈ R , x ≠ - 5

6 0
3 years ago
Select the solutions of the equation. <br> 2x2-3x-5=0
meriva

Using the Quadratic formula

your answer would be A and C

5 0
3 years ago
Read 2 more answers
Can someone help me with this please?
Karolina [17]
For the first image can you give us the choices for each one?
5 0
2 years ago
12<br> Using side lengths only, could the triangles be similar?<br> 0.5<br> m05 1 1.5
Murljashka [212]

Answer:

\large\boxed{\text{No.}\ \dfrac{0.5}{1}\neq\dfrac{1}{1.5}\neq\dfrac{1.5}{2}}

Step-by-step explanation:

\text{Let}\\ a,\ b,\ c\ -\ \text{sides of a triangle ABC, where}\ a\leq b\leq c\\d,\ e,\ f\ -\ \text{sides of a triangle}\ DE F,\ \text{where}\ d\leq e\leq f.\\\\\triangle ABC\sim\triangle DE F\iff\dfrac{a}{d}=\dfrac{b}{e}=\dfrac{c}{f}\\\\/\text{corresponding sides are in proportion}/

\bold{WARNING !!!}\\\\\text{No triangle like QRS exists!}\\\\1 + 0.5 = 1.5 !!!\\\\\text{The sum of the lengths of the two shorter sides of the triangle}\\\text{must be greater than the length of the longest side.}

\text{Despite this, let's check the ratios}

\text{We have:}\\\\\triangle XYZ\to a=1,\ b=1.5,\ c=2\\\triangle QRS\to d=0.5,\ e=1,\ f=1.5

\text{Check:}\\\\\dfrac{d}{a}=\dfrac{0.5}{1}=0.5\\\\\dfrac{e}{b}=\dfrac{1}{1.5}=\dfrac{10}{15}=\dfrac{2}{3}\\\\\dfrac{f}{c}=\dfrac{1.5}{2}=\dfrac{15}{20}=\dfrac{3}{4}\\\\\dfrac{d}{a}\neq\dfrac{e}{b}\neq\dfrac{f}{c}\neq\dfrac{d}{a}

8 0
3 years ago
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