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Alja [10]
3 years ago
8

Please Help me! Marvin worked for 3 days. He earned $87.20 each day. He uses his earnings to buy four chairs. If he has no money

left over, what is the cost of each chair?
$65.40
$261.60
$116.27
$21.80
Mathematics
2 answers:
Molodets [167]3 years ago
5 0

Answer:

21.8

Step-by-step explanation:

87.2 divided by 4

musickatia [10]3 years ago
3 0

Answer:

261.60

Step-by-step explanation:

its 3 times 87.20

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2 1/2+x=5 1/3 PLEASE HELP
erastova [34]

Answer:

Step-by-step explanation:

2 1/2 + x = 5 1/3                Change the mixed numbers to improper fractions

5/2 + x = 16/3                   The lowest common multiple is 6. Multiply by 6

5*3 + 6x = 16*2

15 + 6x = 32                      Subtract 15 from both sides.

6x = 32 - 15

6x = 17                              Divide by 6

6x/6 = 17/6

x = 2 5/6

Check

5/2 + 17/6 = 16/3

15/6 + 17/6 = 32/6

32/6 = 32/6                    The question checks.

7 0
2 years ago
½ is the same as 0.5 and the ratio of _____.
Crazy boy [7]
1:2

Similar to the 1/2 fraction, 1:2 is a simplified ratio of a half.
6 0
3 years ago
Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:
professor190 [17]

Answer:

Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is \{1,2,3,4\}.

a) We need to find a relation R reflexive and transitive that contain the relation R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}

Then, we need:

1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,

2. Observe that

  • 1R4 and 4R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 4R1 and 1R2, then 4 must be related with 2.

Therefore \{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\} is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

  • since 1R2, then 2 must be related with 1.
  • since 1R4, 4 must be related with 1.

and the analysis for be transitive is the same that we did in a).

Observe that

  • 1R2 and 2R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 2R1 and 1R4, then 2 must be related with 4.
  • 4R1 and 1R2, then 4 must be related with 2.
  • 2R4 and 4R2, then 2 must be related with itself

Therefore, the smallest relation containing R1 that is symmetric and transitive is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

c) We need a new relation reflexive, symmetric and transitive containing R1.

For be reflexive

  • 1 must be related with 1,
  • 2 must be related with 2,
  • 3 must be related with 3,
  • 4 must be related with 4

For be symmetric

  • since 1R2, 2 must be related with 1,
  • since 1R4, 4 must be related with 1.

For be transitive

  • Since 4R1 and 1R2, 4 must be related with 2,
  • since 2R1 and 1R4, 2 must be related with 4.

Then, the smallest relation reflexive, symmetric and transitive containing R1 is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

5 0
3 years ago
Crystal bowled two games for a total score of 202. Her score for the first game was 30 points less than the score of her first g
vlada-n [284]
X + x -30 = 2022x - 30 = 2022x = 232x =116 first game = 116second game = 116 - 30 = 86116 + 86 = 202 second game = 86
6 0
3 years ago
Read 2 more answers
George Keller, a small-engine mechanic, earns a regular hourly rate of $15.68. For overtime, he earns time and
Darina [25.2K]

Answer:

$1,034.88

Step-by-step explanation:

since he earns time and a half on Saturdays, he gets $23.52 per hour. on Sundays,he earns double time, it is $31.36 per hour. when you multiply his regular rate per hour with 40, you have $627.20. His Saturday rate with 8, $188.16. And his Sunday rate with 7, $219.52. Add all those together, and you have an answer!

hope I helped...

7 0
3 years ago
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