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saveliy_v [14]
3 years ago
6

I need an answer quick, please and thank you.

Mathematics
2 answers:
Inessa [10]3 years ago
7 0

Answer:

get some ice and see how much it ways

Step-by-step explanation:

vovangra [49]3 years ago
3 0

Answer:

The answer is 216

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i know the answer now is 540 after 3 hours of trying to figure out the "least common multiple" but what does the 3rd number "10"
OLga [1]
It is either A,B, Pr D. It will at the least have to be a common multiple of 10.
6 0
3 years ago
a team of scientists estimate the current number of butterflies In A park to be 20 thousand. the butterfly population is expecte
DiKsa [7]

 Current number of butterflies in the park = 20 thousand.


 Rate of increase of butterfly population = 4% = 0.04


The population of butterfly after 1 year = 20+0.04*20 = 20*1.04


The population of butterfly after 2 years =  20*1.04 + 20*1.04*0.04 = 20*1.04*1.04


 The population of butterfly after 3 years =  20*1.04*1.04 + 20*1.04*1.04*0.04 = 20*1.04*1.04*1.04


So, population of butterfly after n years = 20*(1.04*1.04*1.04* .... n times)


                                                                 



3 0
3 years ago
Read 2 more answers
The radius of a circle is 1 inch. What is its circumference?<br> sorry
Norma-Jean [14]
The answer would be 6 inches!
6 0
3 years ago
Read 2 more answers
You were given a $20,000 gift towards University education by your grandparents. How much will this be in 17 years if it is inve
Nat2105 [25]

Answer:

$65,068.44

Step-by-step explanation:

A= 20000(1+ 0.07/4)^4(17)

A= 20000(1.0175)^68

A= 65,068.44

3 0
3 years ago
Read 2 more answers
The radius of a right circular cone is increasing at a rate of 1.9 in/s while its height is decreasing at a rate of 2.2 in/s. At
musickatia [10]

Answer:

Volume of the cone is increasing at the rate 9916\pi \frac{in^3}{s}.

Step-by-step explanation:

Given: The radius of a right circular cone is increasing at a rate of 1.9 in/s while its height is decreasing at a rate of 2.2 in/s.

To find: The rate at which volume of the cone changing when the radius is 134 in. and the height is 136 in.

Solution:

We have,

\frac{dr}{dt} =1.9 \:\text{in/s}, \frac{dh}{dt}=-2.2\:\text{in/s}, r=134 \:\text{in}, h=136\:\text{in}

Now, let V be the volume of the cone.

So, V=\frac{1}{3}\pi r^{2}h

Differentiate with respect to t.

\frac{dv}{dt} =\frac{1}{3}\pi \left [ r^2\frac{dh}{dt}+h\left ( 2r \right )\frac{dr}{dt} \right ]

Now, on substituting the values, we get

\frac{dv}{dt} =\frac{1}{3}\pi\left [ \left ( 134 \right )^2\left ( -2.2 \right )+\left (  136\right )\left ( 2 \right )\left ( 134 \right )\left ( 1.9 \right ) \right ]

\frac{dv}{dt} =\frac{1}{3}\pi\left [  -39503.2+69251.2 \right ]  

\frac{dv}{dt} =\frac{1}{3}\pi\left [ 29748 \right ]

\frac{dv}{dt} =9916\pi \frac{in^3}{s}

Hence, the volume of the cone is increasing at the rate 9916\pi \frac{in^3}{s}.

6 0
3 years ago
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