All categories

3 years ago

Pls help................

Mathematics

1 answer:

koban [17]3 years ago

5 0

Hi i got 9cm
i replaced each block with the variable x
i set the first line of blocks equal to the second line of blocks
then solved for x
x=9

You might be interested in

(2x + 7y = -24 18x+y=12 solve by substitution

const2013 [10]

Answer:

x = .87, or when approximated to a fraction, 27/31

y = -3.67, or when approximated to a fraction, -1287/350

Step-by-step explanation:

Lets start by rewriting out our equations

2x + 7y = -24

18x + y = 12

Lets solve for a y value; the second equation is easiest, as the y value has no coefficient (the number that is multiplied times a variable). To do this, lets move the 18x to the other side. Now our two equations look like:

2x + 7y = -24

y = -18x + 12

Next, lets plus the second equation into the first equation in regards to y.

2x + 7(-18x + 12) = -24

Now, lets solve!

2x -126x + 84 = -24

Then, combine your terms!

-124x = -108

Divide by (-124)!

x = -108/-124

x = 27/31

Now that we know x, lets plug this back in to the first equation to find y!

2(27/31) + 7y = -24

1.74 + 7y = -24

7y = -25.74

y = -3.67, or when approximated to a fraction, -1287/350

4 0

4 years ago

Two trains leave stations 330 miles apart at the same time and travel toward each other. One train travels at 65 miles per hour

BARSIC [14]

Answer:

Both trains will meet at 2.2 hours (2 hours and 12 minutes).

Step-by-step explanation:

Relative Speed

If two moving objects are traveling through the same line and have speeds v1 and v2 respectively, their relative speed is vr = v1-v2.

Both trains travel toward each other, which means their speeds are of opposite signs.

Let's assume the first train has a positive speed of 65 mph, and the second train has a negative speed of -85 mph. Then, the relative speed is vr = 65 + 85 = 150 mph.

To calculate the time they take to meet, we apply the formula:

$\displaystyle t=\frac{x}{vr}$

$\displaystyle t=\frac{330}{150}=2.2\ hours$

Both trains will meet at 2.2 hours (2 hours and 12 minutes).

6 0

3 years ago

Trigonometry

Allisa [31]

Hey there!

To start, you must use the distance formula which is $\sqrt{(x1-x2)^{2}+(y1-y2)^{2} }$ .

x1 and x2 are the x coordinates of the points (it does not matter which one you assign to be x1 and x2) and y1 and y2 are the y coordinates (also does not matter which one you assign to be y1 and y2).

Now, set up your formula and simplify:

$\sqrt{(x1-x2)^{2}+(y1-y2)^{2} }$

$\sqrt{(-12-13)^{2}+(6-8)^{2} }$

= $\sqrt{629}$ ≈ 25.0799

4 0

4 years ago

Read 2 more answers

Consider the exponential function: f(x) = 3(Five-fourths) Superscript x

gizmo_the_mogwai [7]

Answer: Initial Value: 3 Base: 5/4 Domain: (-infinity, infinity) Range: (0, infinity)

Step-by-step explanation:

Function: y = 3(\frac{5}{4} )^{x}

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Ctext%7BSolve%20for%20x%3A%7D%5C%5C4x%20%2B%2054%20%3D%2055%5C%5C%5C%5C%5Ctext%7BThank%20you

Crazy boy [7]

Hi there!

»»————-　★　————-««

I believe your answer is:

$x = \frac{1}{4}$

»»————-　★　————-««

Here’s why:

⸻⸻⸻⸻

$\boxed{\text{Solving the equation for x...}}\\\\4x + 54 = 55\\----------\\\rightarrow 4x + 54 - 54 = 55 - 54\\\\\rightarrow 4x = 1\\\\\rightarrow \frac{4x=1}{4}\\\\\rightarrow \boxed{x=\frac{1}{4}}$

⸻⸻⸻⸻

»»————-　★　————-««

Hope this helps you. I apologize if it’s incorrect.

6 0

3 years ago

Read 2 more answers