The probability that a three shows on at least one of the dice is 11/36.
<h3>How to calculate the probability?</h3>
It should be noted that of probability means the likelihood of the occurence of an event.
The probability that a three shows on at least one of the dice will be:
= 11/36
This can be seen from the table that is attached.
The probability that the total is less than 8 will be:
= 21/36
= 7/12
Here, there are 21 places where the total is less than 8.
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Answer:
Step-by-step explanation:
its a
Answer:
7,000
Step-by-step explanation:
Answer:
x = 65/16, y = 37/16
Step-by-step explanation:
solve the system algebraically
x+3y=11
4x-4y=7
Try substitution.
let x = 11 - 3y
Plug in.
4(11 - 3y) - 4y = 7
44 - 12y - 4y = 7
44 - 16y = 7
37 = 16y
y = 37/16
x = 11 - 3*y
x = 11 - 3*(37/16)
x = 11 - 111/16
x = 65/16
You did not give us the equation so we can't answer that. Update it and I will try to help.