Answer:
there is no greatest load
Step-by-step explanation:
Let x and y represent the load capacities of my truck and my neighbor's truck, respectively. We are given two relations:
x ≥ y +600 . . . . . my truck can carry at least 600 pounds more
x ≤ (1/3)(4y) . . . . . my truck carries no more than all 4 of hers
Combining these two inequalities, we have ...
4/3y ≥ x ≥ y +600
1/3y ≥ 600 . . . . . . . subtract y
y ≥ 1800 . . . . . . . . multiply by 3
My truck's capacity is greater than 1800 +600 = 2400 pounds. This is a lower limit. The question asks for an <em>upper limit</em>. The given conditions do not place any upper limit on truck capacity.
The radius is half of the diameter.
To find the circumference, use the equation C=2(pi)r or C=(pi)d.
r meaning radius. d meaning diameter.
(pi) is about 3.14 or 22/7
My dude its 9 brubh ni99a isis
Answer:
The answer is option D.
Step-by-step explanation:
Hope this helps you
Find two numbers with a sum of 20 and a difference of 14
Make two equations
X+Y=20
X-Y=14
Now add x since y cancels out and add 20+14 To end up with
2x=34
Now divide 2 both sides to get x alone
2x/2=34/2
X=17
Now substitute x answer to first equation and solve for y
17+y=20
Subtract 17 both sides
Y= 3
Your two numbers are
3 and 17
