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The lengths of pregnancies are normally distributed with a mean of days and a standard deviation of days. a. Find the probabilit

Alik [6]

Answer:

a) The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b) We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Mean $\mu$ , standard deviation $\sigma$

a. Find the probability of a pregnancy lasting X days or longer.

The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b. If the length of pregnancy is in the lowest a%, then the baby is premature. Find the length that separates premature babies from those who are not premature.

We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

8 0

3 years ago

The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend?

MatroZZZ [7]

Answer:

a. $x = 6d^5 - 2c^3d^2 + 5c^2d^3 - 12cd^4 + 8$

Step-by-step explanation:

Given that

$8d^5 + 3c^3d62 + 5c^2d^3 - 4cd^4 + 9$

Now

if one is added i.e.

$2d^5 - c^3d^2 + 8cd^4 + 1$

Now let us assume the other polynomial be x

So,

$8d^5 + 3c^3d62 + 5c^2d^3 - 4cd^4 + 9 = x + (2d^5 - c^3d^2 + 8cd^4 + 1)\\\\x = 8d^5 + 3c^3d62 + 5c^2d^3 - 4cd^4 + 9 - (2d^5 - c^3d^2 + 8cd^4 + 1)\\\\$

$x = (8d^5 - 2d^5) + (-3c^3d^2 + c^3d^2) + 5c^2d^3+ (-4cd^4-8cd^4) + (9-1)\\\\x = 6d^5 - 2c^3d^2 + 5c^2d^3 - 12cd^4 + 8$

8 0

3 years ago

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How much did it cost summer to to buy 2.6 pounds of granola at the old price

coldgirl [10]

It was $6.00 per pound. So 2 pounds would be $12. But there is still that .6 of a pound left. If we know 1 pound costs $6, then we know 1/10th of a pound will cost $0.60. So 6 x .60 = 3.60. Add 12 and 3.60, and you get 15.60 for 2.6 pounds of granola at the old price.

6 0

3 years ago

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Enter the correct number word to complete the conversion. 1 milliampere = one ? of an ampere

Lerok [7]

Answer:

One milliampere is equal to 0.001 ampere.

Step-by-step explanation:

Mili, refers to thousandth. (for example, millimeter or milliliter.)

6 0

2 years ago

If you borrow $500 from a credit union at 12% annual interest and $250 from a bank at 18% annual interest, what is the effective

Gnesinka [82]

Answer:

B. 11.85% = 12%

Step-by-step explanation:

500 * .10 + 300 * .15 = 50 + 45 = 95.

95/800 = .11875

.11875 = 11.875%

8 0

3 years ago

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