Answer:
5 yd³
Step-by-step explanation:
2 in = 1/6 ft
15 ft × 18 ft × 1/6 ft = 45 ft³
1 ft³ = 9 yd³
45 ft³/9 = 5 yd³
This are the formulas hope they help
Step-by-step explanation:
(5√2-4√3)(5√2-4√3)=
(5√2-4√3)^2=(5√2)^2+(4√3)^2-2(5√2)(4√3)
=25*2+16*3-10√2*4√3
=50+48-10√2*4√3
=98-10√2*4√3 is the answer
<span>The maxima of a differential equation can be obtained by
getting the 1st derivate dx/dy and equating it to 0.</span>
<span>Given the equation h = - 2 t^2 + 12 t , taking the 1st derivative
result in:</span>
dh = - 4 t dt + 12 dt
<span>dh / dt = 0 = - 4 t + 12 calculating
for t:</span>
t = -12 / - 4
t = 3
s
Therefore the maximum height obtained is calculated by
plugging in the value of t in the given equation.
h = -2 (3)^2 + 12 (3)
h =
18 m
This problem can also be solved graphically by plotting t
(x-axis) against h (y-axis). Then assigning values to t and calculate for h and
plot it in the graph to see the point in which the peak is obtained. Therefore
the answer to this is:
<span>The ball reaches a maximum height of 18
meters. The maximum of h(t) can be found both graphically or algebraically, and
lies at (3,18). The x-coordinate, 3, is the time in seconds it takes the ball
to reach maximum height, and the y-coordinate, 18, is the max height in meters.</span>
Answer:
perpendicular
Step-by-step explanation:
3y = x + 4 in slope intercept form y = 1/3x +4/3
3x + y = 1 in slope intercept form y = -3x +1
the slopes are negative reciprocals of each other so they are perpendicular
