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mafiozo [28]
3 years ago
12

Can you please find mJPK?

Mathematics
1 answer:
belka [17]3 years ago
3 0

Answer:66.5

Step-by-step explanation:

Let θ represent ∠MLK

Arc length (s) = radius (r) · θ   (theta must be in radians)

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Which ordered pair can be included in the table of values shown below for the equation p=25x-2?
pishuonlain [190]

Answer:

(0,-2)

Step-by-step explanation:

So since you are given the equation, p=25x-2, all you really need to do is plug in the ordered pairs and see which satisfies the equation.

This means makes both side have the same number value.

Let's try (x,p)=(-2,-2):

 p=25x-2 with (x,p)=(-2,-2)

-2=25(-2)-2

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-2=-52

-2 and -52 do not represent the same number so (-2,-2) is not a point on the given line.

Let's try (x,p)=(-2,0):

p=25 x -2 with (x,p)=(-2,0)

0=25(-2)-2

0=-50-2

0=-52

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Let's try (x,p)=(0,-2):

p=25 x  -2 with (x,p)=(0,-2)

-2=25(0)-2

-2=0   -2

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-2 and -2 are the same number and so (0,-2) is a point on the line.

Let's try (x,p)=(0,0)

p=25 x  -2 with (x,p)=(0,0)

0 =25(0)-2

0 =  0   -2

0 =   -2

0 and -2 are not the same number so (0,0) is not a point on this line.

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The awnser would be 17.

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Answer:

I'll sub ig.

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