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3 years ago

6

PLS HELP FAST

1 answer:

vesna_86 [32]3 years ago

6 0

Step-by-step explanation:

$consider \: \: {2x}^{2} - 13x + 15 = 0 \\ (2x - 3)(x - 5) = 0 \\ 2x - 3 = 0 \: \: \: \: \: or \: \: \: \: \: x - 5 = 0 \\ x = 1 \frac{1}{2} \: \: \: \: \: or \: \: \: \: \: x = 5 \\ \\ \\ hence \: the \: products \: of \: zero \: are \: x = 1 \frac{1}{2} \: and \: x = 5$

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