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3 years ago

PLS HELP FAST

Mathematics

1 answer:

vesna_86 [32]3 years ago

6 0

Step-by-step explanation:

$consider \: \: {2x}^{2} - 13x + 15 = 0 \\ (2x - 3)(x - 5) = 0 \\ 2x - 3 = 0 \: \: \: \: \: or \: \: \: \: \: x - 5 = 0 \\ x = 1 \frac{1}{2} \: \: \: \: \: or \: \: \: \: \: x = 5 \\ \\ \\ hence \: the \: products \: of \: zero \: are \: x = 1 \frac{1}{2} \: and \: x = 5$

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Step-by-step explanation:

So your solution would be:

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Just try to remember PEMDAS.

Parenthesis, Exponent, Multiplication/Division, Addition/Subtraction.

This is the order we follow when going about expressions with many operations.

Let's start with the parenthesis part. Notice that there is an exponent beside the parenthesis enclosing the fraction. Here we use the quotient to a power rule. We distribute the exponent to the numerator and the denominator.

$=(\frac{3}{5})^{2} + 4 \times 3 - 2\\$

$=\dfrac{3^{2}}{5^{2}} + 4 \times 3 - 2$

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We have a fraction so we do that first. Then we do the multiplication after.

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$=0.36 + 12 - 2$

Next we do the addition/subtraction. Again, whichever comes first.

$=12.36 - 2$

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