<u>Answer:</u> The concentration of ethyl ethanoate at equilibrium is 
<u>Explanation:</u>
Given values:
Equilibrium concentration of ethanol = 
Equilibrium concentration of ethanoic acid =
The given chemical equation follows:
The expression of 
for above equation follows:
![K_c=\frac{[C_2H_5OH][CH_3COOH]}{[CH_3COOC_2H_5]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BC_2H_5OH%5D%5BCH_3COOH%5D%7D%7B%5BCH_3COOC_2H_5%5D%7D)
Putting values in above expression, we get:
![0.27=\frac{0.42\times 0.42}{[CH_3COOC_2H_5]}](https://tex.z-dn.net/?f=0.27%3D%5Cfrac%7B0.42%5Ctimes%200.42%7D%7B%5BCH_3COOC_2H_5%5D%7D)
![[CH_3COOC_2H_5]=\frac{0.42\times 0.42}{0.27}=0.653mol/dm^3](https://tex.z-dn.net/?f=%5BCH_3COOC_2H_5%5D%3D%5Cfrac%7B0.42%5Ctimes%200.42%7D%7B0.27%7D%3D0.653mol%2Fdm%5E3)
Hence, the concentration of ethyl ethanoate at equilibrium is
Answer: See explanation
Explanation:
Based on the information given in the question, the ranking from the first step to the last step goes as follows:
1. Dissolution of salt into cations and anions
2. Hydration of anions
3. Hydration of cations
4. Dissolved cations and anions begin to deposit as a solid salt.
5. Rate of dissolution is equal to the rate of recrystallization.
Answer:
your answer should be B ANDC
The second one, I could be mistaken though
Answer: 3.29 × 1023 atoms
