If I have eight numbers and i am tasked to decide which of the set of given numbers is the smallest comparing 2 numbers at a time, I will have 28 comparisons in all. Trying all combinations for the first number, you have 7. Trying all combinations for the second number nit including its comparison to the first number (because it will be redundant), you will have 6 comparisons an so on. Adding it all up, you have 7+6+5+4+3+2+1=28.
Answer: D
Step-by-step explanation:
We are given X = 15 - 4y so simply replace any and all X's in the first equation with (15 - 4y). Option D is the best because the X is removed and replaced with the proper writing.
Answer:
For the given equation, x = 21.
Step-by-step explanation:
Here, the lines represent the set of two intersecting lines.
And, the given angles (2x +42) and (4x) are VERTICALLY OPPOSITE ANGLES.
So, (2 x +42) = (4 x)
⇒ 42 = 4 x - 2 x
or, 2 x = 42
⇒ x = 42 /2 = 21
⇒ x = 21
Hence, for the given equation, x = 21.
