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morpeh [17]
3 years ago
10

What is 65 times 753 I dont wanna use a calculator

Mathematics
2 answers:
Stolb23 [73]3 years ago
7 0

Answer:

48945

Step-by-step explanation:

Butoxors [25]3 years ago
4 0

Answer:

48945

Step-by-step explanation:

lol gang gang

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Need answer please show work
Jet001 [13]

Let us set up some variabe:

  • height: h
  • base: b

Use the known information:

  • b = 2h + 8

Now lets find the area

   Area = (1/2) * b *h = (1/2) * h * (2h + 8)

Hope that helps!

7 0
2 years ago
Quadratic equations of the form _____ can be solved using square roots
icang [17]

Answer:

Step-by-step explanation:

Quadratic equations of the form (x - h)^2 + k = 0 can be solved using square roots:  Take the square root of both sides, prefacing the right side with " ± "

6 0
3 years ago
What is 3 over 4 + b = 3
FromTheMoon [43]

Answer:

2 and 1/4

Step-by-step explanation:

3/4 + b = 3

rearrange the equation

3 - 3/4 = b

3/1 - 3/4 = 14/4 - 3/4 = 11/4 = 2 and 1/4

4 0
2 years ago
What is another solution of the equation<br><br> x + y = 7?
White raven [17]
X=3, y=4
x=-2, y=9
Set x equal to anything, then isolate y to get the other number.
5 0
3 years ago
Find the curl of ~V<br> ~V<br> = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k
ch4aika [34]

Given

\vec v =  f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k

the curl of \vec v is

\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k

\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k

\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k

7 0
3 years ago
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