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valentinak56 [21]

3 years ago

8

A ball is thrown horizontally at the speed of 24 meters per second from the top of a cliff. If the ball hits the ground 6.0 seco

nds later, approximately how high is the cliff?

1 answer:

Anon25 [30]3 years ago

4 0

Answer:

$h=4m$

Step-by-step explanation:

Speed $V=24m/s$

Time $t=6.0s$

Generally the equation for Height is mathematically given by

$h=\frac{V}{t}$

$h=\frac{24}{6}$

$h=4m$

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