Question

A ball is thrown horizontally at the speed of 24 meters per second from the top of a cliff. If the ball hits the ground 6.0 seconds later, approximately how high is the cliff?

Answer 1

Answer:

$h=4m$

Step-by-step explanation:

Speed $V=24m/s$

Time $t=6.0s$

Generally the equation for Height is mathematically given by

 $h=\frac{V}{t}$

 $h=\frac{24}{6}$

 $h=4m$