Answer:
pretty sure its A hope this helps!
A 65-year-old Caucasian female who
smokes presents with increased urinary frequency dysuria, and sporadic,
painless hematuria. Most likely the client’s follow up will be cytoscopy. It
is a procedure where a doctor introduces a tube through urethra
and into the bladder to
visualize the inside of the bladder.
C. When one population cannot interbreed with the other population.
Answer:
The cell is the basic unit of all organisms, and all cells come from existing cells
Explanation:
<span>Answer:
TT=90
Tt=420
tt= 490
When there is 2 type of allele, there will be 3 possible genotypes: homozygous dominant, heterozygous, homozygous recessive. Dominant phenotype will be expressed for </span>homozygous dominant and heterozygous. That mean, the number of homozygous would be:
TT+Tt= 510
total population= TT + Tt + tt
1000= 510 + tt
tt=490
The frequency of recessive allele would be:
t= √(490/1000)= √0.49= 0.7
After that, you can find the frequency of the dominant allele
T+t= 1
T+0.7=1
T=0.3
Using both frequency, you can find the number of homozygous dominant (TT) and heterozygous (Tt) population
TT= 0.3 *0.3 * 1000 individuals = 90 individuals
Tt= 2 * 0.3 * 0.7 * 1000 <span>individuals</span>= 420 individuals
