The value of the differential with respect to x is -xy/x²+ay
<h3>Implicit differentiation</h3>
Given the following function
x²y +ay² = b
We are to differentiate implicitly with respect to x
x²dy/dx + 2xy + 2aydy/dx = 0
(2x²+2ay)dy/dx = -2xy
dy/dx = -xy/x²+ay
Hence the value of the differential with respect to x is -xy/x²+ay
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Answer:
width = 2 units
Step-by-step explanation:
If the length of a rectangle is (x) units, then that means that the width of a rectangle is x - 4 units.
the area of a rectangle is length * width
so just substitute the values that we have now.
x (length) * (x-4) width = 12 (area of rectangle)
so that gives us
x^2 - 4x =12
subtract 12 from both sides
x^2 - 4x - 12 =0
now factor this equation
x^2 + 2x - 6x -12 = 0
x(x+2) - 6(x+2) = 0
(x-6)(x+2) = 0
x = 6, or x = -2 REMEMBER THAT VALUE OF x = LENGTH, IT CANNOT BE NEGATIVE AS YOU CANT HAVE NEGATIVE VALUE OF A SIDE
length = 6, and width = 6 -4 = 2
Answer:
Step-by-step explanation:
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