6. Using the picture of the pre-image figure, computate the image coordinate values using the transformation given. dilation of
2.5
1 answer:
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Answer: Its light-collecting area would be 25 times greater than that of the 10-meter keck telescope.
Step-by-step explanation:
1. To solve this problem you must apply the formula for calculate the area of a circle, which is shown below:
Where<em> r</em> is the radius of the circle.
2. The diameter of a circle is:
Where <em>r</em> is the radius of the circle.
3. Therefore, keeping this on mind, you have that the light-collecting area of a 50-meter keck telescope is:
4. And the light-collecting area of a 10-meter keck telescope is:
5. Divide by
, then:
6. Therefore, its light-collecting area would be 25 times greater than that of the 10-meter keck telescope.
Answer:
5.055 m by 13.055 m
Step-by-step explanation:
Let x represent the width of the room in meters. Then the length is x+8 meters, and the room area is ...
A = LW = (x+8)(x) = 2(rug area)
x^2 +8x = 2(3)(11) = 66
Completing the square, we have ...
x^2 +8x +16 = 82
(x +4)^2 = 82
x = -4 ±√82 ≈ {-13.055, +5.055}
The magnitudes of these dimensions are the dimensions of the room:
√82 ± 4 = {5.055, 13.055} . . . meters
Therefore, the room is 5.055 × 13.055 meters.
