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Katyanochek1 [597]
3 years ago
6

10 is 70% of what number? If necessary, round to the nearest tenth.

Mathematics
2 answers:
stiv31 [10]3 years ago
6 0
0.7X = 10

10 / 0.7 = 14.23
Sergio [31]3 years ago
5 0

Answer:

The required answer is 7.

Step-by-step explanation:

=10*70/100

=7

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Which expression is equivalent to 4x-5? select all that apply
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A&C

Step-by-step explanation:

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3 years ago
A new surgical procedure is successful with probability of p. Assume that the operation is performed 5 times and the results are
DaniilM [7]

Answer:

a) P(X=5)=(5C5)(0.8)^5 (1-0.8)^{5-5}=0.32768

And we can use the following excel code: "=BINOM.DIST(5,5,0.8,FALSE)"

b) P(X=4)=(5C4)(0.6)^4 (1-0.6)^{5-4}=0.2592

And we can use the following excel code: "=BINOM.DIST(4,5,0.6,FALSE)"

c) P(X

And the excel code would be: "=BINOM.DIST(1,5,0.3,TRUE)"

d) E(X) =n*p= 5*0.5 =2.5

e) Var (X) = np(1-p) = 5*0.4*(1-0.4)=1.2

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we know that:

X \sim Binom(n=5, p)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

For this case the value of p =0.8 and we want to find this probability:

P(X=5)=(5C5)(0.8)^5 (1-0.8)^{5-5}=0.32768

And we can use the following excel code: "=BINOM.DIST(5,5,0.8,FALSE)"

Part b

For this case the value of p =0.6 and we want this probability:

P(X=4)=(5C4)(0.6)^4 (1-0.6)^{5-4}=0.2592

And we can use the following excel code: "=BINOM.DIST(4,5,0.6,FALSE)"

Part c

The value of p assumed is 0.3. For this case we want this probability:

P(X

P(X=0)=(5C0)(0.3)^4 (1-0.3)^{5-0}=0.16807

P(X=1)=(5C1)(0.3)^4 (1-0.3)^{5-1}=0.36015

P(X

And the excel code would be: "=BINOM.DIST(1,5,0.3,TRUE)"

Part d

The expected value for the binomial distribution is given by np and since we are assuming p=0.5 we got:

E(X) =n*p= 5*0.5 =2.5

Part e

Assuming the value of p=0.4. The variance for the binomial distribution is given by:

Var (X) = np(1-p) = 5*0.4*(1-0.4)=1.2

7 0
3 years ago
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