Answer: c=24
Step-by-step explanation: 15×3=45. 8×3=24. Just multiply both the numerator and denominator by 3.
A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 4 liters of a 50% iodine mixture?
.
Let x = liters of 40% iodine
then
4-x = liters of 80% iodine
Using algebra:
.40x + .80(4-x) = .50(4)
.40x + 3.20-.80x = 2
3.20-.40x = 2
x = 4 liters (40% iodine)
80% iodine:
4-x = 4-4 = 0 liters needed (80% iodine)
Answer:
1/2 gallons
Step-by-step explanation:
since 1/3of the tank is already full and another 4 gallons fills it up
4 gallons= 2/3 of the tank or the tank is 6 gallons total
75% is equal to 3/4
6*3/4=4 1/2 gallons
since it is 1/3 or 4 gallons full
4 1/2 -4= 1/2