OK well take out the 6 for the first form
= 6(2x^2 + x + 4)
Also we can factor the first 2 terms to give the second form:-
= 6x(2x + 1) + 24
(x - 1)(x - 2)(x + 2)
note that the sum of the coefficients 1 - 1 - 4 + 4 = 0
thus x = 1 is a root and (x - 1 ) is a factor
dividing x³ - x² - 4x + 4 by (x - 1)
x³ - x² - 4x + 4 = (x - 1)(x² - 4 ) (note (x² - 4 ) is a difference of squares )
x³ - x² - 4x + 4 = (x - 1)(x - 2)(x + 2)
(x - 1)(x - 2)(x + 2 ) =0
x - 1 = 0 ⇒ x = 1
x - 2 = 0 ⇒ x = 2
x + 2 = 0 ⇒ x = - 2
solutions are x = 1 or x = ± 2
Answer:
0.15
Step-by-step explanation:
The 1st figure is correct, the 4th one seems very similar to the 1st one. But the red shape is closer to line k. So the 1st one is correct
The answer would be 893.4
