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mixas84 [53]
3 years ago
6

Please teash me how to do​

Mathematics
1 answer:
MatroZZZ [7]3 years ago
4 0

Answer:x=40

Step-by-step explanation: So since we know that AD is parallel to BC  We know that M<c and M<a are congruent so we can use this equation to solve for x

2x-20= x+20

    +20    +20

2x=x+40

-x      -x

x=40

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A man pays a total of 4800 in flat rental for 3 months. find the man monthly rental rate.
Elza [17]

Answer:

<u>1,600</u>

Step-by-step explanation:

divide the total money by the time to get unit rate such as 4800 divided by 3 equals <u>1600</u>

Also can you give brainliest to all of your questions bc it really hard to get brainliest and it be really nice you can choose who i dont really care but just please do it it helps a lot

3 0
3 years ago
Given that k-5, k+7, k+55 are three consecutive terms in a geometric sequence, solve for k​
choli [55]

Answer:

k = 9

Step-by-step explanation:

Given:

Consecutive Terms:  k-5, k+7, k+55

Required:

Determine the value of k

To do this, we make use of the concept of common ratio.

The common ratio (r) of a geometric sequence is:

r = \frac{T_{n}}{T_{n-1}}

In other words:

r = \frac{T_3}{T_2} = \frac{T_2}{T_1}

Where 1, 2 and 3 represents the terms of the progression/sequence

So:

r = \frac{T_3}{T_2} = \frac{T_2}{T_1} becomes

\frac{k+55}{k+7} = \frac{k+7}{k-5}

Cross Multiply:

(k+55)(k-5) = (k+7)(k+7)

Open Brackets

k^2 + 55k - 5k - 275 = k^2 + 7k + 7k + 49

k^2 + 50k- 275 = k^2 + 14k + 49

Collect Like Terms

k^2 - k^2 + 50k-14k  = 275 + 49

36k  = 324

Solve for k

k = 324/36

k = 9

5 0
4 years ago
20 points!!<br> -3 + w = -6<br><br> please help me write out my problem like this
murzikaleks [220]

Answer:

w=-3

Step-by-step explanation:

-3+w=-6 = original problem

w=-6+3 = u add 3 because u have it was negative so if u bring it to the other side u have to make it positive

w=-3 = answer

3 0
3 years ago
Read 2 more answers
Which is equivalent to 3 cube root 125
aleksklad [387]
Do you mean 3 \sqrt[3]{125} or \sqrt[3]{125}
remember that \sqrt[n]{x^m}=x^\frac{m}{n}
resolve the \sqrt[3]{125} part first\sqrt[3]{125}=\sqrt[3]{5^3}=5^\frac{3}{3}=5^1=5

so
3 \sqrt[3]{125}=3*5=15 or \sqrt[3]{125} =5not sure which one you mean
7 0
3 years ago
Read 2 more answers
If p(x) = 2x2 - 4x and g(x) = x - 3, what is (pog)(x)?
stira [4]

Answer:

<h2>2x² - 16x + 30</h2>

Step-by-step explanation:

p(x) = 2x² - 4x

g(x) = x - 3

To find (pog)(x) replace every x in p(x) by g(x)

That's

(pog)(x) = 2(x - 3)² - 4(x - 3)

= 2( x² - 6x + 9) - 4x + 12

= 2x² - 12x + 18 - 4x + 12

<h3>= 2x² - 16x + 30</h3>

Hope this helps you

3 0
3 years ago
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