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Schach [20]
3 years ago
11

Which variable has the most impact on growing your money? If you could increase one of the variables in the compound interest fo

rmula, which would have the most impact on growing your money? Before you complete the next set of calculations, predict whether an increase in the principal, the rate, or the frequency of compounding will increase your account balance more.
Mathematics
1 answer:
postnew [5]3 years ago
3 0

Answer:

I would increase the number and multiply

Step-by-step explanation:

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3 years ago
Plzzzzz answer this question about density mass and volume!!!!!!!!!
nataly862011 [7]

Answer:

13.896 kg

Step-by-step explanation:

You can find the mass of the bar by first finding the volume.

V = BH

where B = area of the base (the trapezium), and

H = height (distance trapezium between bases)

The area of a trapezium is

A = (b1 + b2)h/2

where b1 and b2 are the lengths of the bases of the trapezium (the parallel sides), and

h = the altitude of the trapezium (distance between the bases of the trapezium)

V = (b1 + b2)h/2 * H

V = (12 cm + 6 cm)(5 cm)/2 * 16 cm

V = 720 cm^3

The volume of the bar is 720 cm^3.

Now we use the density and the volume to find the mass.

density = mass/volume

mass = density * volume

mass = 19.3 g/cm^3 * 720 cm^3

mass = 13,896 g

Now we convert grams into kilograms.

1 kg = 1000 g

mass = 13,896 g * (1 kg)/(1000 g)

mass = 13.896 kg

Answer: 1.3896 kg

6 0
3 years ago
Consider the solution to the linear equation. 5 (x + 6) = 50. 5 x + 30 = 50. 5 x = 20. x = 4. Which describes the inverse operat
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(trying to isolate/get x by itself in the equation)

5(x + 6) = 50      Distributive property   [distribute 5 into (x + 6)]

5x + 30 = 50    Subtraction    [subtract 30 on both sides of the equation]

5x = 20       Division     [divide 5 on both sides]

x = 4

Subtraction then division, the 2nd option

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3 years ago
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If the point (2, -10) lies on the graph of a direct variation, which represents the direct variation equation?
Zanzabum

\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x}{2},\stackrel{y}{-10})~~ \textit{we know } \begin{cases} x=2\\ y=-10 \end{cases}\implies -10=k2\implies \cfrac{-10}{2}=k\implies -5=k \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-5x~\hfill

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