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3 years ago

G= {(6,9), (-2, 2), (0, -2), (6, -3)}

Mathematics

1 answer:

nekit [7.7K]3 years ago

5 0

Answer:

The domain is 4, range is 5

Step-by-step explanation:

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During halftime of a football game a slingshot launches T-shirts at the crowd a T-shirt is launched from a height of 6 feet with

lesantik [10]

Answer:

2.25 seconds

87 feet

[6, 87]

Step-by-step explanation:

The height of a projectile is:

h(t) = -16t² + vt + s

where v is the initial vertical velocity and s is the initial height.

Here, v = 72 and s = 6.

h(t) = -16t² + 72t + 6

This is a downwards parabola. The maximum is at the vertex.

t = -b / (2a)

t = -72 / (2×-16)

t = 2.25

h(2.25) = 87

It takes 2.25 seconds to reach the maximum height of 87 feet.

The range is from the lowest height (6 feet) to the maximum height (87 feet). In interval notation:

[6, 87]

5 0

4 years ago

A 12-cm-long thin rod has the nonuniform charge density λ(x)=(2.0 nC/cm)e−|x|/(6.0 cm), where x is measured from the center of t

Inessa [10]

Answer:

the total charge is

$Q=24(1-\exp(-1))nC\approx15.171nC$

Step-by-step explanation:

Since x is measured from the center, that means that x=0 is the center so the edges of the rod correspond to x=-6 and x=6. that meas that the total charge can be calculated as

$Q=\int^{6}_{-6}2\exp\left(\frac{-|x|}{6}\right)dx$

separating the integral from -6 to 0 and from 0 to 6, taking into account that |x|=-x for x<0 and |x|=x for x >=0, we get $Q=\int^{0}_{-6}2\exp\left(\frac{x}{6}\right)dx+\int^{6}_{0}2\exp\left(\frac{-x}{6}\right)dx$

using the substitution x=-u in the first integral we get $\int^{0}_{-6}2\exp\left(\frac{x}{6}\right)dx=-\int^{0}_{6}2\exp\left(\frac{-u}{6}\right)du=\int^{6}_{0}2\exp\left(\frac{-u}{6}\right)du$

which is the same as the first integral. Thus, the total charge is given by

$Q=2\int^{6}_{0}2\exp\left(\frac{-x}{6}\right)dx$

integrating we get

$Q=4(-6\exp\left(\frac{-x}{6}\right))\big|^{6}_{0}=-24(\exp(-6/6)-\exp(0))=24(1-\exp(-1))$

4 0

3 years ago

A rural mail carrier logged the mileage on the odometer at the start of the mail route as 31,500 miles. After 6.5 hours, the car

disa [49]

Answer:

Step-by-step explanation:

Average speed = total distance / total time taken

Average speed is the total distance traveled divided by the total time taken

The carrier first odometer route is

d_1 = 31,500 miles

On return of the truck, the odometer reads

d_2 = 31,713 miles

The total time taken is 6.5 hours on return

Then,

Average Speed = total distance / total time.

A.V = (d_1 + d_2) / t

A.V = (31,500 + 31713) / 6.5

A.V = 63213 / 6.5

A.V = 9725.1 mile per hour

A.V = 9725.1 mph

3 0

4 years ago

Simplify i3 a. -I b. -1 c. I d. 1

Sholpan [36]

i3 simplified is c. I

6 0

3 years ago

Read 2 more answers

20 points!! plz help!

Mandarinka [93]

Answer:

This is the answer of your question. ☺☺

Step-by-step explanation:

1. 4b+2

2 4x-1

3 False

4 5b^2 -b-2

7 0

3 years ago