-3q – 19 = 19 – 5q<br> q=

Help please!!!!!!!!!!!

ss7ja [257]

First, solve 7 times square root of 5.

7 x 2.236 = 15.652

Now find the solution above that results in 15.65.

We can quickly eliminate the top 2 as they will result in very large numbers.

The bottom problem is quick to check - simplifies to (7 + 5)/5 = 2.4. No

It looks like the next to last answer is our best bet.

Figure the square root of 196 (14) and multiply by square root of 5 (2.236). Giving us 31.304.

Divide the result by 2. And that gives us 15.652.

If you knew the square root of 196 was 14, it was helpful to find this quickly because 14/2 = 7 and then the other square root was the 5 from the problem.

5 0

3 years ago

A manager randomly selected 25 large cash transactions at a bank that were made in January. The manager then carefully tracked d

Dmitriy789 [7]

Answer:

0.4629 = 46.29% probability that the manager finds more than two such transactions

Step-by-step explanation:

For each transaction, there are only two possible outcomes. Either there is a procedural error, or there is not. The probability of a procedural error on a transaction is independent of any other transaction. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A manager randomly selected 25 large cash transactions at a bank that were made in January.

This means that $n = 25$

The chance for a procedural error is 10%

This means that $p = 0.1$

What is the probability that the manager finds more than two such transactions?

This is:

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{25,0}.(0.1)^{0}.(0.9)^{25} = 0.0718$

$P(X = 1) = C_{25,1}.(0.1)^{1}.(0.9)^{24} = 0.1994$

$P(X = 2) = C_{25,2}.(0.1)^{2}.(0.9)^{23} = 0.2659$

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0718 + 0.1994 + 0.2659 = 0.5371$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5371 = 0.4629$

0.4629 = 46.29% probability that the manager finds more than two such transactions

4 0

3 years ago

What is the distance between (7,0) and (7,-9)

Naddika [18.5K]

Answer:

9 units

Step-by-step explanation:

You can use the distance formula, or you could recognize that since both points have the same x-coordinate, they lie on a vertical line, so the distance between them would be the absolute value of 0 and -9, which is 9.

Hope this helped! :) (Srry I was a little late)

5 0

3 years ago

Read 2 more answers

In a certain small town, 3 professional burglars are currently out of prison: Alex, Becky, and Carl. Alex has in the past commit

NeX [460]

Answer:

Answer explained below

Step-by-step explanation:

Alex has in the past committed 55% of the burglaries committed by the three, Becky 31%, and Carl the rest, hence

probability, P(Carl doing a burglary) = 1 - P(Alex or Becky doing a burglary)

= 1 - (0.55 + 0.31)

= 0.14

a) P(next burglary in town is the burglary of a residence) = P(Alex did a burglary of a residence) + P(Becky did a burglary of a residence) + P(Carl did a burglary of residence

= 0.55*1/3 + 0.31*0.5 + 0.14*1

= 0.4783

b)From Bayes' Theorem: P(A | B) = P(A & B) / P(B)

Hence,

P(Becky | a resident reports a home burglary) = P(Becky did a burglary of a residence) / P(burglary of a residence)

= (0.31 * 0.5)/0.4783

= 0.3240

3 0

3 years ago

If x =5 find the value of 2x squared

Bas_tet [7]

Answer:

100

Step-by-step explanation:

2(5)^2

10^2

100

4 0

3 years ago

-3q – 19 = 19 – 5q q=