Answer:
<h2>The answer is 0.1493.</h2>
Step-by-step explanation:
In a standard deck there are 52 cards in total and there are 4 aces.
Two cards can be drawn from the 52 cards in 
ways.
There are (52 - 4) = 48 cards rather than the aces.
From these 48 cards 2 cards can be drawn in 
ways.
The probability of choosing 2 cards without aces is 
.
The probability of getting at least one of the cards will be an ace is 
.
Answer:
10 hours to readm240
Step-by-step explanation:
Answer:
well, this answer is considered unavailable equals. this means the question is being asked wrong. none of the answers are correct as there is no way to make an available answer from the statement.
I think that the sum will always be a rational number
let's prove that
<span>any rational number can be represented as a/b where a and b are integers and b≠0
</span>and an integer is the counting numbers plus their negatives and 0
so like -4,-3,-2,-1,0,1,2,3,4....
<span>so, 2 rational numbers can be represented as
</span>a/b and c/d (where a,b,c,d are all integers and b≠0 and d≠0)
their sum is
a/b+c/d=
ad/bd+bc/bd=
(ad+bc)/bd
1. the numerator and denominator will be integers
2. that the denominator does not equal 0
alright
1.
we started with that they are all integers
ab+bc=?
if we multiply any 2 integers, we get an integer
<span>like 3*4=12 or -3*4=-12 or -3*-4=12, etc.
</span>even 0*4=0, that's an integer
the sum of any 2 integers is an integer
like 4+3=7, 3+(-4)=-1, 3+0=3, etc.
so we have established that the numerator is an integer
now the denominator
that is just a product of 2 integers so it is an integer
<span>2. we originally defined that b≠0 and d≠0 so we're good
</span>therefore, the sum of any 2 rational numbers will always be a rational number <span>is the correct answer.</span>
Answer:
3
Step-by-step explanation:
Function B looks like y = 3x + 4
with Function A being y = 9x + 4
9 is 3 times more than 3
