Do you need answer for all paper
Answer: No, x+3 is not a factor of 2x^2-2x-12
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Explanation:
Let p(x) = 2x^2 - 2x - 12
If we divide p(x) over (x-k), then the remainder is p(k). I'm using the remainder theorem. A special case of the remainder theorem is that if p(k) = 0, then x-k is a factor of p(x).
Compare x+3 = x-(-3) to x-k to find that k = -3.
Plug x = -3 into the function
p(x) = 2x^2 - 2x - 12
p(-3) = 2(-3)^2 - 2(-3) - 12
p(-3) = 12
We don't get 0 as a result so x+3 is not a factor of p(x) = 2x^2 - 2x - 12
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Let's see what happens when we factor p(x)
2x^2 - 2x - 12
2(x^2 - x - 6)
2(x - 3)(x + 2)
The factors here are 2, x-3 and x+2
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Answer:
(c) g(x) = 1/3·f(x)
Step-by-step explanation:
You can pick a point, such as the vertex at (2, -3) on f(x) and see which of the transformations gives you a point on the graph of g(x).
You will find that g(x) represents a vertical scaling by a factor of 1/3, so ...
g(x) = 1/3·f(x)
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The point (2, -3) on f(x) corresponds to the point (2, -1) on g(x).
Your answer would be a=-6.12
Answer:
A i think but i think not also try it
