Question

Can someone help me find the length of b of the unknown side in this triangle? Thanks! :)

Answer 1

Answer: 4

Step-by-step explanation:

Using pythagoras theorem =>

b=$\sqrt{c^2-a^2$

b=$\sqrt{5^2-3^2}$

b=$\sqrt{25-9}$

b=$\sqrt{16}$

b=4

Answer 2

Answer:

4

Step-by-step explanation:

Use the Pythagorean Theorem:

$a^2+b^2=c^2$

The measure of the hypotenuse is 5. The measure of the given leg is 3.

$3^2+b^2=5^2\\\rightarrow 3^2 = 9; 5^2=25\\9+b^2=25\\9-9+b^2=25-9 \leftarrow \text {Subtraction Property of Equality} \\b^2=16\\\sqrt{b^2}=\sqrt{16} \leftarrow \text {Square Root Property of Equality}\\\boxed {b=4}$

The unknown side of the triangle should be four units.