Question

The number of carbon atoms in 9.30x10^-3 moles of Na2CO3​

Answer 1

Answer: $56\times 10^{20}\ \text{atoms}$

Explanation:

Given

No. of moles of $Na_{2}CO_{3}$ is $9.30\times 10^{-3}$

So, for $9.30\times 10^{-3}$ moles of $Na_{2}CO_{3}$

There are $9.30\times 10^{-3}\times 6.022\times 10^{23}\ \text{molecules of}\ Na_{2}CO_{3}=56\times 10^{20}\ \text{molecules}$

1 molecule of  $Na_{2}CO_{3}$ contains 1 atom of carbon

i.e. there are $56\times 10^{20}\ \text{atoms of C}$