✿————✦————✿————✦————✿
The answer is: <u>2(k2−4k)(2c+5)</u>
✿————✦————✿————✦————✿
Step:
* Consider 2ck2+5k2−8ck−20k. Do the grouping 2ck2+5k2−8ck−20k=(2ck2+5k2) +(−8ck−20k), and factor out k2 in the first and −4k in the second group.
* Factor out the common term 2c+5 by using the distributive property.
* Rewrite the complete factored expression.
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Answer:
Step-by-step explanation:
Given the equation y = 2,5x
y is the height of the water
x is the time.
To get the range of values of the height at t = 60s, we will substitute x = 60 into the function
y = 2.5(60)
y = 150 in
Hence the range of the situation is [0, 150].
The domain will be all positive integers i.e xEZ
3(y-7)
use distributive property
