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3 years ago

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Can someone please help on my geometry test?

1 answer:

sveta [45]3 years ago

5 0

THE ANSWER IS NOT IN THE LINK THAY THAT PERSON GAVE

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Guys help me with this question please. Due Now

boyakko [2]

F(5) = 21
look on the table and find where x=5 on the top row, the number that is with it is 21

f(x) = 7
x=6
look on the table and find where f(x)=7 on the bottom row, the number with it is 6

6 0

3 years ago

What is e+f/g in distributive property

enot [183]

Answer:

e/g+f/g

Step-by-step explanation:

(e+f)/g can be split up. e/g+f/g is equal to (e+f)/g so your answer is e/g +f/g

7 0

3 years ago

Write each expression as a product of linear factors 1. X^2+1/2x 2. X^2+2x-3 3. (2x-3)^2 4. X^3+2x^2-19x-20

Grace [21]

Answer:

1. X^2+1/2x = $x(x+\frac{1}{2})$

2. X^2+2x-3 = $(x-1)(x+3)$

3. (2x-3)^2 = (2x-3)(2x-3)

4. X^3+2x^2-19x-20 = $(x+1)(x-4)(x+5)$

Step-by-step explanation:

Each expression can be written as a product of linear factors as follows

1. X^2+1/2x ⇒ $x^{2} + \frac{1}{2}x$

$x^{2} + \frac{1}{2}x$ = $x(x+\frac{1}{2})$

Hence, X^2+1/2x = $x(x+\frac{1}{2})$

2. X^2+2x-3 ⇒ $x^{2} +2x-3$

$x^{2} +2x-3 = x^{2} +3x-x-3$

$x^{2} +3x-x-3 = x(x+3) -1(x+3)$

$x(x+3) -1(x+3) = (x-1)(x+3)$

Hence, X^2+2x-3 = $(x-1)(x+3)$

3. (2x-3)^2 ⇒ $(2x-3)^{2}$

$(2x-3)^{2} = (2x-3)(2x-3)$

Hence, (2x-3)^2 = (2x-3)(2x-3)

4. X^3+2x^2-19x-20 ⇒ $x^{3}+2x^{2} -19x -20$

$x^{3}+2x^{2} -19x -20 = (x+1)(x^{2} +x-20)$

First,

$x^{2} +x-20 = x^{2} +5x-4x-20\\x^{2} +5x-4x-20= x(x+5)-4(x+5)\\x(x+5)-4(x+5) = (x-4)(x+5)$

∴ $(x+1)(x^{2} +x-20) = (x+1)(x-4)(x+5)$

Hence, X^3+2x^2-19x-20 = $(x+1)(x-4)(x+5)$

3 0

3 years ago

How do I write a numerical expression for 5 times the sum of 3 and 4

vitfil [10]

5(3+4)first you would add 3 and 4 and then multiply 5 to it

6 0

3 years ago

5x−y=3<br> −5x+2y=4<br> Which ordered pair satisfies the system of equations shown above?

ale4655 [162]

Answer:

$(2, 7)$

Step-by-step explanation:

We can solve this system of equations by using elimination.

In this case, we can eliminate x by adding the two equations:

$5x+(-5x)-y+2y=3+4\\5x-5x+y=7\\y=7$

Then, substitute 7 for y to solve for x:

$5x-y=3\\5x-7=3\\\text{Add 7 to both sides}\\5x=10\\\text{Divide both sides by 5}\\x=2$

Substitute both these values into the system to check our answer:

$5x-y=3\\5(2)-7=3\\10-7=3\\3=3\rightarrow \text{correct!}$

$-5x+2y=4\\-5(2)+2(7)=4\\-10+14=4\\4=4\rightarrow \text{correct!}$

Therefore the ordered pair is:

$(x, y)=(2, 7)$

6 0

2 years ago