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2 years ago

A(2, -1), B(-4, -4) HELP THIS IS ALGEBRA PLEASE HELP

Mathematics

1 answer:

shtirl [24]2 years ago

3 0

Step-by-step explanation:

y2-y1

----------

x2-x1

-4-(-1)

------------

-4-2

=0,5

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What focal-length eyepiece is needed if your eye can resolve objects 0.10 mm apart at a distance of 25 cm?

Kay [80]

M=d/f so, f=d/M f=25/.01. =2500cm

7 0

3 years ago

Chance can wash the car in 2 hours, while Sandy can wash the same car in 4 hours. How many hours would it take for them to wash

aliya0001 [1]

Answer: First Option is correct.

Step-by-step explanation:

Since we have given that

Number of hours Chance can wash the car = 2 hours

Number of hours Sandy can wash the car = 4 hours

Work done by Chance per hour is given by

$\frac{1}{2}$

Work done by Sandy per hour is given by

$\frac{1}{4}$

Work done by altogether per hour is given by

$\frac{1}{2}+\frac{1}{4}\\\\=\frac{2+1}{4}\\\\=\frac{3}{4}$

So, Number of hours they take if they together wash the car is given by

$\frac{4}{3}$

Hence, First Option is correct.

6 0

2 years ago

Read 2 more answers

I need help with this question

beks73 [17]

Answer:

1024

Step-by-step explanation:

1 division: 2

2 divisions: 2×2 = 4

3 divisions: 2×(2×2) = 8

The number of viruses is 2^n, where n is the number of divisions.

After 10 divisions, there are 2^10 = 1024 viruses.

4 0

2 years ago

Please help, I’m struggling

Naddika [18.5K]

Answer:

49.5 mi

Step-by-step explanation:

Area of a triangle is A = (height) X (base) / 2

So if you plug in the numbers you get:

806.9 = (32.6) X (base) / 2

1613.8 = (32.6) X (base)

1613.8 / 32.6 = base

base = 49.5 mi

8 0

2 years ago

3. The curve C with equation y=f(x) is such that, dy/dx = 3x^2 + 4x +k

Andreas93 [3]

a. Given that y = f(x) and f(0) = -2, by the fundamental theorem of calculus we have

$\displaystyle \frac{dy}{dx} = 3x^2 + 4x + k \implies y = f(0) + \int_0^x (3t^2+4t+k) \, dt$

Evaluate the integral to solve for y :

$\displaystyle y = -2 + \int_0^x (3t^2+4t+k) \, dt$

$\displaystyle y = -2 + (t^3+2t^2+kt)\bigg|_0^x$

$\displaystyle y = x^3+2x^2+kx - 2$

Use the other known value, f(2) = 18, to solve for k :

$18 = 2^3 + 2\times2^2+2k - 2 \implies \boxed{k = 2}$

Then the curve C has equation

$\boxed{y = x^3 + 2x^2 + 2x - 2}$

b. Any tangent to the curve C at a point (a, f(a)) has slope equal to the derivative of y at that point:

$\dfrac{dy}{dx}\bigg|_{x=a} = 3a^2 + 4a + 2$

The slope of the given tangent line $y=x-2$ is 1. Solve for a :

$3a^2 + 4a + 2 = 1 \implies 3a^2 + 4a + 1 = (3a+1)(a+1)=0 \implies a = -\dfrac13 \text{ or }a = -1$

so we know there exists a tangent to C with slope 1. When x = -1/3, we have y = f(-1/3) = -67/27; when x = -1, we have y = f(-1) = -3. This means the tangent line must meet C at either (-1/3, -67/27) or (-1, -3).

Decide which of these points is correct:

$x - 2 = x^3 + 2x^2 + 2x - 2 \implies x^3 + 2x^2 + x = x(x+1)^2=0 \implies x=0 \text{ or } x = -1$

So, the point of contact between the tangent line and C is (-1, -3).

7 0

2 years ago