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makvit [3.9K]
3 years ago
9

A(2, -1), B(-4, -4) HELP THIS IS ALGEBRA PLEASE HELP

Mathematics
1 answer:
shtirl [24]3 years ago
3 0

Step-by-step explanation:

y2-y1

----------

x2-x1

-4-(-1)

------------

-4-2

=0,5

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kirza4 [7]
I think 5.55 will travel in 3.7 seconds
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3 years ago
What is the value of x?
timama [110]

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The triangles ADB and BDC are similar.  Thus it is possible to write an equation of ratios and solve it for x:

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Describe the end behavior of the function f(x)=-2x^4- x^3 +3.
Hoochie [10]

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B

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6 0
2 years ago
Solve the problem, calculate the line integral of f along h
Over [174]
The curve \mathcal H is parameterized by

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You are mistaken in thinking that the gradient theorem applies here. Recall that for a scalar function f:\mathbb R^n\to\mathbb R, we have gradient \nabla f:\mathbb R^n\to\mathbb R^n. The theorem itself then says that the line integral of \nabla f(x,y,z)=\mathbf f(x,y,z) along a curve C parameterized by \mathbf r(t), where a\le t\le b, is given by

\displaystyle\int_C\mathbf f(x,y,z)\,\mathrm d\mathbf r=f(\mathbf r(b))-f(\mathbf r(a))

Specifically, in order for this theorem to even be considered in the first place, we would need to be integrating with respect to a vector field.

But this isn't the case: we're integrating f(x,y,z)=y^2, a scalar function.
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