Answer:
½ sec²(x) + ln(|cos(x)|) + C
Step-by-step explanation:
∫ tan³(x) dx
∫ tan²(x) tan(x) dx
∫ (sec²(x) − 1) tan(x) dx
∫ (sec²(x) tan(x) − tan(x)) dx
∫ sec²(x) tan(x) dx − ∫ tan(x) dx
For the first integral, if u = sec(x), then du = sec(x) tan(x) dx.
∫ u du = ½ u² + C
Substituting back:
½ sec²(x) + C
For the second integral, tan(x) = sin(x) / cos(x). If u = cos(x), then du = -sin(x) dx.
∫ -du / u = -ln(u) + C
Substituting back:
-ln(|cos(x)|) + C
Therefore, the total integral is:
½ sec²(x) + ln(|cos(x)|) + C
(50/4) + (6/4) is the answer that you are looking for. All you do is break up the number that you are going to divide into easy-to-divide numbers.
"Per" means "divided by", so "cost per ounce" means "cost"/"ounces".
The difference in cost per ounce is
.. (1.14/12) -(1.28/16) = .095 -.08 = 0.015
Brand X costs 1.5¢ more per ounce than Brand Y.
12 and -1 are two numbers that multiply to -12 and add up to 11
Answer:
C
Step-by-step explanation:
