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Assoli18 [71]
3 years ago
15

Can someone plz help me with this one problem!!!

Mathematics
2 answers:
puteri [66]3 years ago
8 0
No because 9 is x and if you substitute it in the equation it’ll be y = 9 + 9 = 18 but in the coordinate it is 0
Lina20 [59]3 years ago
4 0

Answer:

Yes

Step-by-step explanation:

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Which set of shapes could you use to form a net for a
Hoochie [10]

Answer:

A

Step-by-step explanation:

I did the assignment :>

5 0
3 years ago
Read 2 more answers
During a concert, $3280 was received. A total of 760 people attended. Reserved seats were $6 and general admission seats were $4
Andre45 [30]

Answer:

The number of reserved seat is 120 and number of general seat is 640.

Step-by-step explanation:

Given,

Total number of seats = 760

Total collected Money = $3280

Solution,

Let the total number of reserved seat be x.

And  the total number of general seat be y

Hence total number of seats is the sum of total number of reserved seat and  the total number of general seats.

So the equation can be written as;

x+y=760\ \ \ \ equation\ 1

Again, total money collected is the sum of fees of one reserved seat times total number of reserved seat and fees of one general seat times the total number of general seats.

So the equation can be written as;

6x+4y=3280\ \ \ \ \ equation\ 2

Now, multiplying equation 1 by 4 and then subtract it from equation 2.

4x+4y=3040

(6x+4y)-(4x+4y)=3280-3040\\\\2x=240\\\\x=\frac{240}{2}=120

On substituting the value of x in equation 1, we get;

x+y=760\\120+y=760\\y=760-120=640

Thus the number of reserved seat is 120 and number of general seat is 640.

8 0
3 years ago
1.9 x (1/4) answer as a fraction
Elan Coil [88]

Answer:

19/40 1.9x0.25=0.475= 19/40

7 0
3 years ago
A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon
fiasKO [112]

Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that n = 603, \pi = \frac{142}{603} = 0.2355

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

8 0
2 years ago
Solve for z w(-4+z)=Mz+17
bogdanovich [222]

Answer:

z = \frac{17+4w}{w-M}

Step-by-step explanation:

6 0
3 years ago
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