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3 years ago

Can someone plz help me with this one problem!!!

Mathematics

2 answers:

puteri [66]3 years ago

8 0

No because 9 is x and if you substitute it in the equation it’ll be y = 9 + 9 = 18 but in the coordinate it is 0

Lina20 [59]3 years ago

4 0

Answer:

Yes

Step-by-step explanation:

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Find the distance between (2, 2) and (-4, 4). Round answer to the nearest tenth.

Naya [18.7K]

Answer:

6.3

Step-by-step explanation:

First off, we need the distance formula, which is:

$\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

If we plug in the points, we get:

$\sqrt{(-4 - 2)^2 + (4 - 2)^2}$

If we simplify everything under the square root, we get:

$\sqrt{(-6)^2 + (2)^2}$

$\sqrt{36 + 4}$

$\sqrt{40}$

In decimal, the answer is 6.3

6 0

3 years ago

Write an equation of the function

ohaa [14]

Answer:

g(x) = |x-3| -4

Step-by-step explanation:

to shift right by 3, subtract three from x inside the absolute value.

to shift down by 4, subtract 4 outside of the absolute value.

g(x) = |x-3| -4

5 0

3 years ago

Please awnser and make sure it’s to

AlekseyPX

Answer:

the third one

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

PLEASSSSSEEE NEED HELP ASAP ALOT OF POINTS BIGGG POINTS PLEASSSS

Elena-2011 [213]

2. x = 8, -4
|x-2|
2 * x-2=12
2x-4=12
2x=16
x=8
-4 - 2 = -6
-6 x 2 = 12

3 0

3 years ago

Use the given information to find the unknown value:y varies directly as the square of z. When x = 2, then y= 20. Find y when 2

Vladimir79 [104]

Answer

y = 45 when x = 3

Step-by-step explanation:

$\begin{gathered} \text{Given that y varies directly as the square of x} \\ \text{This implies that there is a positive relationship betwe}en\text{ y and the square of z} \\ \text{Mathematically, this can be expressed as} \\ y\text{ }\propto x^2 \\ To\text{ turn this expression into an equation, we n}eed\text{ to introduce a proportionality constant k} \\ y=kx^2 \\ \text{ According to the question, y = 20 and x = 2} \\ \text{From the above informaion we can find our k} \\ y=kx^2 \\ 20\text{ = k }\cdot2^2 \\ 20\text{ = k }\cdot\text{ 4} \\ \text{Divide both sides by 4} \\ \frac{20}{4}\text{ = }\frac{k\cdot\text{ 4}}{4} \\ k\text{ = 5} \\ \text{ Find y when }x\text{ = 3} \\ y=kx^2 \\ y\text{ = 5 }\cdot(3)^2 \\ y\text{ = 5 }\cdot\text{ 9} \\ y\text{ = 45} \end{gathered}$

8 0

1 year ago