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Kay [80]
3 years ago
8

HELP ASAPPP

Mathematics
2 answers:
Yuri [45]3 years ago
6 0

Answer:

B,C

Step-by-step explanation:

7(4)-1=27

28-1=27

46-8(4)=14

46-32=14

rewona [7]3 years ago
3 0

Answer:

B & C

Step-by-step explanation:

A) does not even have an x, but prentening the z i san x?, 9*4= 36. 36+22= 14.

B) 7*4= 28, 28-1=27

C) 8*4= 32, 46-32= 1

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Find the trigonometric ratio for cos B may need to use Pythagorean theorem
iragen [17]

Answer:

The answer is cos B = 2/3

I hope it will help you :)

7 0
3 years ago
Simplify assuming x is a positive number √x^16+16x^8
bogdanovich [222]
\sqrt{x^{16} + 16x^8}

\sqrt{x^8(x^{8} + 16)}

x^4\sqrt{(x^{8} + 16)}


4 0
4 years ago
15 – (3 + 4) + 7 x 2 – 3 2
blondinia [14]

Answer:

-10

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Step-by-step explanation:

<u>Step 1: Define</u>

15 - (3 + 4) + 7 × 2 - 32

<u>Step 2: Evaluate</u>

  1. (Parenthesis) Add:                    15 - 7 + 7 × 2 - 32
  2. Multiply:                                     15 - 7 + 14 - 32
  3. Subtract:                                    8 + 14 - 32
  4. Add:                                           22 - 32
  5. Subtract:                                    -10
5 0
3 years ago
A bakery sold 96 vanilla cupcakes in a day, which was 48% of the total number of cupcakes sold that day. How many total cupcakes
RideAnS [48]

Step-by-step explanation:

96/x =48%/100

48x=9600

x=9600/48

x=200 cakes

8 0
3 years ago
(sin^2x+tan^2x+cos^2x)/(sec^2x) What trig identities are used in solving this as well.
Vinil7 [7]

The main one is the Pythagorean identity,

sin²(<em>x</em>) + cos²(<em>x</em>) = 1

By dividing both sides by cos²(<em>x</em>), you get the tan-sec variant:

sin²(<em>x</em>)/cos²(<em>x</em>) + cos²(<em>x</em>)/cos²(<em>x</em>) = 1/cos²(<em>x</em>)

tan²(<em>x</em>) + 1 = sec²(<em>x</em>)

since tan(<em>x</em>) = sin(<em>x</em>)/cos(<em>x</em>) and sec(<em>x</em>) = 1/cos(<em>x</em>).

So the given expression reduces to

(sin²(<em>x</em>) + tan²(<em>x</em>) + cos²(<em>x</em>)) / sec²(<em>x</em>)

= (1 + tan²(<em>x</em>)) / sec²(<em>x</em>)

= sec²(<em>x</em>) / sec²(<em>x</em>)

= 1

4 0
3 years ago
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