Answer:
11√3-7√6
im good at these, just hit me up if you need more help ;)
The standard error of the mean is 128.125.
The formula for standard error is:
With our information, we have:
Answer:
Population A
Step-by-step explanation:
Think about. If population A already known for normally distribution AND you take large samples. The rest would still be distributed, Which keeps population A a Normal Distribution.
but Population C is nor normally distributed, so if you take away large samples. it will deteriorate its distribution so it won't get any better or in this case, normal. so. it is Population A.
Answer:
$126.33
Step-by-step explanation:
$379/3 = $126.33
Answer:
65625/4(x^5)(y²)
Step-by-step explanation:
Using binomial expansion
Formula: (n k) (a^k)(b ^(n-k))
Where (n k) represents n combination of k (nCk)
From the question k = 5 (i.e. 5th term)
n = 7 (power of expression)
a = 5x
b = -y/2
....................
Solving nCk
n = 7
k = 5
nCk = 7C5
= 7!/(5!2!) ------ Expand Expression
=7 * 6 * 5! /(5! * 2*1)
= 7*6/2
= 21 ------
.........................
Solving (a^k) (b^(n-k))
a = 5x
b = -y/2
k = 5
n = 7
Substituting these values in the expression
(5x)^5 * (-y/2)^(7-5)
= (3125x^5) * (-y/2)²
= 3125x^5 * y²/4
= (3125x^5)(y²)/4
------------------------------------
Multiplying the two expression above
21 * (3125x^5)(y²)/4
= 65625/4(x^5)(y²)
