F(1) = 160 is given to us. We'll use it to find f(2)
f(n+1) = -2*f(n)
f(1+1) = -2*f(1) ... replace every n with 1
f(1+1) = -2*160 ... replace f(1) with 160
f(2) = -320
Now use f(2) to find f(3)
f(n+1) = -2*f(n)
f(2+1) = -2*f(2) ... replace every n with 2
f(3) = -2*(-320) ... replace f(2) with -320
f(3) = 640
Finally, use f(3) to find f(4)
f(n+1) = -2*f(n)
f(3+1) = -2*f(3) ... replace every n with 3
f(4) = -2*640 ... replace f(3) with 640
f(4) = -1280
Final Answer: -1280
The answer is B. because if you make an equation in the form y=mx+b then you can solve the equation by inputting x where x goes in the equation and solving. BTW the equation would be y=2x-1
Segment CF is parallel to segment BE because these segments are side by side and will have the same distance continuously between them. Therefore your answer would be,
Segment BE
∠AOF is the angle that is the supplementary angle to ∠FOD because these are two angles that sum up to 180°. hence, the answer is,
∠AOF
A:
Ratio of all students in the class to girls is...
15:8
b:
Ratio of boys to girls....
7:8
You can find one the picture I send
