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3 years ago

15

Please help meeeeeeeeeee

1 answer:

julsineya [31]3 years ago

8 0

I hope this helped

Step-by-step explanation:

Ok

First : Find the area by using length x width x height

Second: 18in (long/length) x 12in (wide/width) 10in (high/height)

last : 18 x 12 x 10

=2,160 in/ C

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How do i solve this pls

miskamm [114]

First we would solve both x’s
3x^2 - 5x
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Which means you have to multiply it by itself that many times which would be
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9x- 5x = 4x
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7 0

3 years ago

Drag each title to the correct box. Not all tiles will be used

mestny [16]

Answer:

4, 1, 6.

See explanation

Step-by-step explanation:

You are given the equation

$d=vt-\dfrac{1}{2}at^2$

First subtract $vt$ from both sides:

$d-vt--\dfrac{1}{2}at^2$

and multiply the equation by -1:

$vt-d=\dfrac{1}{2}at^2\ \ \ \ (1)$

Now multiply (1) by 2:

$2(vt-d)=at^2\ \ \ \ \ (2)$

At last, divide by $a$

$t^2=\dfrac{2(vt-d)}{a}\ \ \ \ \ (3)$

5 0

3 years ago

Help 15 points!!!!!!!!!!!!!!!!!!!!!

Svetllana [295]

Answer:

see explanation

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan A = $\frac{opposite}{adjacent}$ = $\frac{BC}{AC}$ = $\frac{7}{8}$ , then

∠ A = $tan^{-1}$ ( $\frac{7}{8}$ ) ≈ 41° ( to the nearest degree )

The sum of the angles in the triangle = 180° , then

∠ B + 41° + 90° = 180°

∠ B + 131° = 180° ( subtract 131° from both sides )

∠ B = 49°

Using Pythagoras' identity in the right triangle

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AB = $\sqrt{113}$ ≈ 10.6 ( to the nearest tenth )

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3 years ago

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andriy [413]

The area of the triangle is 12.72unit

5 0

3 years ago

Quadrilateral ABCD?<br>

Mashutka [201]

The given quadrilateral is a kite.

Given: Point A (2, 4), B (-2, -5), C (7, -1) and D (7, 4)

Firstly, we find the distance between AD and DC

AD = $\sqrt{(7 - 2)^{2} + (4 - 4)^{2} }$

⇒ AD = $\sqrt{5^{2} }$

⇒ AD = 5

DC = $\sqrt{(7 - 7)^{2} + (4 - (-1))^{2} }$

⇒ DC = $\sqrt{5^{2} }$

⇒ DC = 5

Hence, AD = DC = 5

Now, find the distance between AB and BC

AB = $\sqrt{(-2 - 2)^{2} + (-5 - 4)^{2} }$

⇒ AB = $\sqrt{(-4)^{2} + (-9)^{2} }$

⇒ AB = $\sqrt{16 + 81}$

⇒ AB = $\sqrt{97}$

BC = $\sqrt{(7 - (-2))^{2} + (-1 - (-5))^{2} }$

⇒ BC = $\sqrt{9^{2} + 4^{2} }$

⇒ BC = $\sqrt{81 + 16}$

⇒ BC = $\sqrt{97}$

Hence, AB = BC = √97

In the given quadrilateral, the two pair is of equal length and these sides are adjacent to each other.

Hence, it follows the property of kite.

For more questions on quadrilateral, visit:

brainly.com/question/23935806

#SPJ9

6 0

1 year ago