A rhombus is always a parallelogram, hope that helps!
Answer: C
Step-by-step explanation:
Reflecting over the x axis, the image of a point in Quadrant 2 is a point in Quadrant 3.
We know that sin2x=2sinxcosx
(search the net for proof if you wish)
So the original equation becomes
2sinxcosx-sinx=0
The two terms both have sinx that can be taken out to get:
sinx(2cosx-1)=0
This is true if sinx=0 or 2cosx-1=0 , rewritten: cosx=1/2
sinx=0 than x=2kπ
cosx=1/2 than x=π/3+2kπ
where k is an integer
Hi there!

f(x) = -2x - 3
Plug in 0 for "x" to solve for f(0):
f(0) = -2(0) - 3
f(0) = -3
Since the question is asking you to evaluate f(0) - 7, simply subtract:
-3 - 7 = -10.
Five less than a number n